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2 years ago

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A basketball player shoots the ball with an initial velocity of 17.1 ft/sec. at an angle of 45.6° with the horizontal. To the ne

arest tenth, find the initial horizontal component of the vector that represents the velocity of the ball.
A. 5.1 ft/sec.
B. 12.0 ft/sec.
C. 12.2 ft/sec.
D. 17.5 ft/sec.

2 answers:

vichka [17]2 years ago

8 0

If a projectile is projected with velocity $u$ at an angle $\theta$ with horizontal, then the horizontal and vertical components of the velocity are

$u\cos \theta,u\sin \theta$ respectively.

Here $u=17.1\;ft/sec$ and $\theta=45.6^o$ .

The horizontal component of the initial velocity is

$17.1\cos (45.6^o)=11.96$ .

The approximate value is $12.0\;ft/sec$ .

Correct choice is (B).

N76 [4]2 years ago

6 0

The answer is B. 12.0 ft/sec

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Answer:

The area of the shaded region is $329.87\ cm^2$

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

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we know that

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