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Agata [3.3K]
2 years ago
13

Rosa says she can break this array(6 rows,8 in each row) into 3 different sets of two smaller arrays.Is Rosa correct.Explain

Mathematics
1 answer:
snow_tiger [21]2 years ago
4 0

Answer:

Rosa is correct

Step-by-step explanation:

Rosa has array 6 \times 8 (6 rows and 8 columns). She can break this array into two smaller arrays in such ways:

  • 1st array 5\times 8 (5 rows and 8 columns) and 2nd array 1\times 8 (1 row and 8 columns);
  • 1st array 4\times 8 (4 rows and 8 columns) and 2nd array 2\times 8 (2 rows and 8 columns);
  • 1st array 3\times 8 (3 rows and 8 columns) and 2nd array 3\times 8 (3 rows and 8 columns);
  • 1st array 6\times 1 (6 rows and 1 column) and 2nd array 6\times 7 (6 rows and 7 columns);
  • 1st array 6\times 2 (6 rows and 2 columns) and 2nd array 6\times 6 (6 rows and 6 columns);
  • 1st array 6\times 3 (6 rows and 3 columns) and 2nd array 6\times 5 (6 rows and 5 columns);
  • 1st array 6\times 4 (6 rows and 4 columns) and 2nd array 6\times 4 (6 rows and 4 columns).

So, there are even more than 3 different ways.

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