Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
Answer:
7.5
Step-by-step explanation:
7.2 + 8.5 + 7.0 + 8.1 + 6.7 = 37.5
37.5÷5 = 7.5
<u>Answer-</u>
The standard error of the confidence interval is 0.63%
<u>Solution-</u>
Given,
n = 2373 (sample size)
x = 255 (number of people who bought)
The mean of the sample M will be,
Then the standard error SE will be,
Therefore, the standard error of the confidence interval is 0.63%
<span>( 7 x - 11 )
<span>( 7 - 5x )</span></span>
She scored better with math
