In general, after a group makes a reservation at a restaurant, they do not show up 20% of the time. If a restaurant has 8 reserv
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System 1: The solution is (x, y) = (-4, 5)
System 2: The solution is
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 7 ------ eqn 1
-3x - 5y = -13 --------- eqn 2
We can solve by elimination method
Multiply eqn 1 by 3
6x + 9y = 21 ------ eqn 3
Multiply eqn 2 by 2
-6x - 10y = -26 ------- eqn 4
Add eqn 3 and eqn 4
6x + 9y -6x - 10y = 21 - 26
-y = -5
y = 5
Substitute y = 5 in eqn 1
2x + 3(5) = 7
2x + 15 = 7
2x = -8
x = -4
Thus the solution is (x, y) = (-4, 5)
<h3><em><u>Second system of equation is:</u></em></h3>8 - y = 3x ------ eqn 1
2y + 3x = 5 ----- eqn 2
We can solve by susbtitution method
From given,
y = 8 - 3x ----- eqn 3
Substitute eqn 3 in eqn 2
2(8 - 3x) + 3x = 5
16 - 6x + 3x = 5
3x = 16 - 5
3x = 11
Substitute the above value of x in eqn 3
y = 8 - 3x
Thus the solution is
We will use ratio to determine how much can Fatima afford as a loan for her house.
Let gross income of Fatima = $ x
Amount earned by Fatima monthly= $ 5,375
36 % of 5,375=
$
Maximum amount that can be paid as a loan monthly = $ 1935
Total money that she can pay yearly for house loan if Fatima allowable money for paying loans is $ 1935=
$
Money saved as a down payment = $ 15,000
So, maximum amount loan Fatima can take on a house= 23220 + 15000=$38,220
She is not allowed for loan for house if the cost of house is any of the four options.
(B) 28 % of $ 5375=
$
Maximum amount that Fatima spend on her house monthly= $ 1505
Amount that fatima can spend yearly on her house = 1505× 12 =$18,060
For the four options given , none of the option matches Fatima's expectations.