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2 years ago

Explain how to find the distance between two integers using the difference.

Mathematics

2 answers:

Gelneren [198K]2 years ago

6 0

Select two numbers on the number line. For this example, the numbers are -8 and 6.

Subtract one number on the number line from the other number. For example, 6 subtracted from -8 is -14.

Obtain the absolute value of the number line difference. For this example, the absolute value for -14 is | |-14|=14. The distance between these two numbers is 14.

Hoochie [10]2 years ago

5 0

Answer:

Find the difference between two integers by adding the additive inverse. The distance is the absolute value of the difference. Check the distance by plotting the original two integers on a number line and counting the units between them.

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The number of people who attended a concert on Friday was 3/4 the number of people who attended the same concert on Saturday. A

LiRa [457]

On Saturday, 4/4 of the amount of people attended. On Friday, 3/4 of the amount on Saturday attended. We have 7 parts (3 from Friday and 4 from Saturday).

840/7 = 120.

Thus, 360 people attend on Friday and 480 on Saturday.

8 0

2 years ago

P=100a÷t solve for a

pishuonlain [190]

a=1/100pt is the correct answer. First you had to multiply by t from both sides of equation, and it gave us, ⇒ $pt=100a$ . And then you had to flip an equation, and it gave us, ⇒ $100a=pt$ . You can also divide by one-hundred (100) from both sides of equation, and it gave us, $\frac{100a}{100}=\frac{pt}{100}$ . And finally, and it gave us the answer is a=1/100pt is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

8 0

2 years ago

Read 2 more answers

A fish tank is three-quarters (3/4) full. two-thirds (2/3) of the water leaks out, leaving 10 gallons of water in the tank. what

Naily [24]

To solve this problem, all we have to do is to thoroughly analyze the situation step by step.

First let us work on the remaining 10 gallons of water in the tank. We are given that 2 / 3 of the water initially in the tank leaked out. Therefore this means that we are left with 1 / 3 the original amount of water which is 10 gallons, hence:

(1 / 3) Vi = 10 gallons

where Vi is the initial volume of water inside the tank, calculating for Vi:

Vi = 3 (10 gallons)

Vi = 30 gallons

We are also given that this initial volume of water is just 3 / 4 of the total capacity of the tank, therefore:

(3 / 4) Vc = Vi

where Vc is the volume capacity of the tank, calculating for Vc:

Vc = 4 Vi / 3

Vc = 4 (30 gallons) / 3

Vc = 40 gallons

Answer:

Capacity of the fish tank is 40 gallons

3 0

2 years ago

The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev

Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 30.05 inches

$\sigma$ = standard deviation = 0.2 inches

n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches) = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z < 3) = 0.99865

P(X bar <= 30.25) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } }$ ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches) = 0.99865 - 0.97725

= 0.0214

7 0

2 years ago

The function H(t) = −16t2 + 48t + 12 shows the height H(t), in feet, of a cannon ball after t seconds. A second cannon ball move

Thepotemich [5.8K]

Part A:
To determine the values of the times to which the height of the two cannon balls are the same, we equate the given functions.
H(t) = g(t)
Substitute the expressions for each.
-16t² + 48t + 12 = 10 + 15.2t

Transpose all the terms to the left-hand side of the equation.
-16t² + (48 - 15.2)t + (12 - 10) = 0

Simplifying,
-16t² + 32.8t + 2 = 0

The values of t from the equation are 2.11 seconds and -0.059 seconds

Part B:
In the context of the problem, only 2.11 seconds is acceptable. This is because the second value of t which is equal to -0.059 seconds is not possible since there is no negative value for time.

8 0

2 years ago