For this problem, we plug in the <em>numbers for t</em> and the <em>appropriate letters for e</em> to the equation <em>e = 300 - 10t</em>.
a) a = 300 - 10(-2)
simplify: a = 300 + 20
simplify: a = 320 ft.
But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.
b) b = 300 - 10(3.5)
simplify: b = 300 - 35
simplify: b = 265 ft.
c) c = 300 - 10(30)
simplify: c = 300 - 300
simplify: c = 0 ft.
Denise is constructing A square.
Note: A square has all sides equal.
We already given two vertices M and N of the square.
And another edge of the square is made by from N.
Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.
Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>
Therefore, correct option is :
D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.
90 inches 18 times 5 is 90 and 30 times 3 is 90 so the lowest point which they will be at the height is 90 inches
Answer:
10 inches.
Step-by-step explanation:
If 1 inch represents 150 miles, and there are 1500 miles covered by the map, then the length of the highway on the map is 10 inches.