<span>0.977
So we have a population with the mean being 0.8750 and the standard deviations being 0.0011. So let's see how many standard deviations we need to be off by to exceed the specifications.
Low end
(0.8725 - 0.8750)/ 0.0011 = -0.0025/0.0011 = -2.272727273
High end
(0.8775 - 0.8750)/ 0.0011 = 0.0025/0.0011 = 2.272727273
So we need to be within 2.272727273 deviations of the mean. Let's use a standard normal table to look up that value, which is 0.48848, which is half the percentage. So 0.48848 * 2 = 0.97696, rounding to 3 digits gives 0.977</span>
I believe the answer is the last one (D), because if n is 33 than 33 + (33+1[34]) = 67.
Answer:
4
Step-by-step explanation:
Let's set up an equation using the formula for the area of a triangle.
Hint #22 / 3
\begin{aligned} \text{Area of a triangle} &= \dfrac12 \cdot \text{base} \cdot \text{height}\\\\ 12&= \dfrac12 \cdot 6 \cdot x \\\\ 12&= 3x \\\\ \dfrac{12}{\blueD{3}}&= \dfrac{3x}{\blueD{3}} ~~~~~~~\text{divide both sides by } {\blueD{ 3}}\\\\ \dfrac{12}{\blueD{3}}&= \dfrac{\cancel{3}x}{\blueD{\cancel{3}}}\\\\ x &=\dfrac{12}{\blueD{3}}\\\\ x &=4\end{aligned}
Area of a triangle
12
12
3
12
3
12
x
x
=
2
1
⋅base⋅height
=
2
1
⋅6⋅x
=3x
=
3
3x
divide both sides by 3
=
3
3
x
=
3
12
=4
To find the total profit, add p(x) and q(x):
(110 + 25x) + (15x + 85)
15x + 25x + 110 + 85 --> group like terms
40x + 195 --> add like terms
p(x) + q(x) = 40x + 195 --> This is the function that represents the total profit for January and February
Step-by-step explanation:
1. C = the graphing is slowly increasing, then he walks across the top so it is flat
2. D = it started out slow and gradually got higher, which is what the story said
3. H = he had to stop walking, and there is a part of no movement in the graph H
4.
