Answer:
(0,-2)
Step-by-step explanation:
It is given that the range of the number of cars sold is 4. Therefore if the fewest cars sold is 3, then the greatest number of cars sold will be 3 + 4 = 7.
The median number of cars sold is 6, so it is possible that the greatest number of cars sold is 7.
The statement is TRUE.
Given
jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.
find out the combined cost of 1 pound of turkey and 1 pound of ham
To proof
As given in the question
jacinta buys 4 pounds of turkey and 2 pounds of ham
total pay by jacinta = $30
let us assume that the price of the ham = x
as given in the question
turkey costs $1.50 less per pound than the ham
turkey costs becomes = x - 1.50
then the equation becomes
30 = 4 (x - 1.50) + 2x
30 = 4x + 2x - 6
36 = 6x
x = 6
thus
ham cost per pound = $6
turkey cost per pound = 6 - 1.50
= $ 4.5
Now find out
cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5
= $ 10.5
Hence proved
Dawson's annual premium will be $2,462.40. This can be found by going across from "Male 40-44" over to "20-year coverage" which is $13.68. Since $13.68 is per $1000 of coverage, you would multiply it by 180 to get $2,462.40.
Rachel's checks I believe would have a deduction of $63.14.
If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y
This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
