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mina [271]
2 years ago
3

A ship travels 10 miles from Point A to Point B, makes a turn of 106 degrees, and travels 14 miles to Point C. If the ship trave

ls directly from Point C back to Point A, how many miles will it travel on the last leg of the trip (from Point C to Point A)? Round your answer to the nearest tenth of a mile.

Mathematics
2 answers:
stiks02 [169]2 years ago
6 0

Answer:

19.32 miles

Step-by-step explanation:

AB =10 miles

∠ABC = 106°

BC = 14 miles

Now we are supposed to find AC

We will use cosine law

c^2=a^2+b^2-2ab cos C

AC^2=AB^2+BC^2-2(AB)(BC) cos 106^{\circ}

AC^2=100+196+77.1784596

AC^2=373.1784596

AC=\sqrt{373.1784596}

AC=19.31782

Thus it will travel 19.32 miles on the last leg of the trip .

laiz [17]2 years ago
3 0
See the attached picture for the solution:

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