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mamaluj [8]
2 years ago
10

Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a

re similar, and 2AC = CF = 2FK. The first pillar, , is 20 meters tall.
The area of ∆CDF is square meters.
Mathematics
1 answer:
Marta_Voda [28]2 years ago
3 0
AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 =  160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
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When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?
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Step-by-step explanation:

Let us revise how to write the exponent as a radical

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Example:

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  • 3^{6} can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
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Now let us solve your problem

∵ 1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}

- Factorize 1250 to its prime factors

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∴ \sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}

∴ \sqrt[4]{1250}=125\sqrt[4]{8}

∴ The value remains under the radical = 8

The value remains under the radical is 8

Learn more:

You can learn more about the radicals in brainly.com/question/7153188

#LearnwithBrainly

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