Ask question

Ask question

All categories

2 years ago

12

The computer lab is replacing the broken computers with 13 wireless touchscreen devices. About what percent of the lab is wirele

ss devices?

1 answer:

Alborosie2 years ago

8 0

How many computers where there in the first place? cool we know how many were replaced but how many were there in the first place?

You might be interested in

the side lengths of a triangle are increased by 50% to make a similar triangle. does the area increase by 50% as well?

Anarel [89]

No. The new area is 2.25 times the original area. That's (1.5 times 1.5).

6 0

2 years ago

Read 2 more answers

Aidan has 6 (different) bulls and 10 (different) horses living at his animal sanctuary. He needs to place them in a line of 16 p

suter [353]

Answer: 5225472000

Step-by-step explanation:

Given : The number of bulls = 6

The number of horses = 10

Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .

Also there are two ways to arrange the group pf bulls and horses.

Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_

$2\times6!\times10!=5225472000$

Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000

7 0

2 years ago

Suppose the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations. Th

madreJ [45]

Answer:

<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.

Step-by-step explanation:

A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.

It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.

The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:

<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.

<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.

The significance level of the test is:

<em>α</em> = 0.05.

The test is defined as:

$z=\frac{(\bar x_{1}-\bar x_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma_{1}^{2}}{n_{1}}+\frac{\sigma_{2}^{2}}{n_{2}}}}$

The decision rule for the test is:

If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.

6 0

2 years ago

24. ABCDE and PQRST are regular pentagons.

SIZIF [17.4K]

Answer:

126°

Step-by-step explanation:

In quadrilateral DSRC, SR || DC (given)

AP = BQ = CR = DS = ET (given)

$\therefore$ CR bisects $\angle DCB$

$\therefore m\angle DCR=\frac{108\degree}{2}$

( $108\degree$ is the measure of an angle of pentagon)

$\therefore m\angle DCR=54\degree$

$\because m\angle DCR + m\angle SRC=180\degree$

(Measure of interior angles on the same side of transversal)

$\therefore 54\degree + m\angle SRC=180\degree$

$\therefore m\angle SRC=180\degree- 54\degree$

$\therefore m\angle SRC=126\degree$

3 0

2 years ago

Solve 16(3x-5) -10(4x-8) = 40

Mashcka [7]

Answer:

x = 5

Step-by-step explanation:

<u>Step 1: Multiply out the brackets</u>

48x - 80 - 40x + 80 = 40 → <em>negative + negative = positive [-10 x -8]</em>

<u>Step 2: Simplify</u>

8x = 40 →<em> collect like terms</em>

<u>Step 3: Solve</u>

x = $\frac{40}{8}$

x = 5

3 0

2 years ago

Read 2 more answers