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frutty [35]
2 years ago
3

The prime factorizations of the denominators of and are given: 10r2 = 2(5)(r)(r) 4r = 2(2)(r) What is the LCD of the expressions

? 4r2 10r2 20r2 40r2
Mathematics
1 answer:
devlian [24]2 years ago
3 0
The LCD of two terms is obtained by multiplying the commonly occurring factors and the non-common factors together. An important thing which must be noted is that the common factor is used only once. For example, in case of 10 and 6. Factors of 10 are 2 and 5, Factors of 6 are 2 and 3. 2 is a common factor and occurs in both terms. While finding the LCD of these 2 , 2 will be multiplied just once with the non-common terms. Similar will be the case with given terms.

Common factors of the given terms are 2 and r
Non-common factors of the given terms are 5, r and 2

The LCD of the given two terms will be = 2r *10r = 20r²
20r² is the smallest number which is divisible by both the given terms. 

So, option C gives the correct answer.
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Rational number 3 by 40 is equals to​
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6/80, 9/120, 12/160 etc

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2 years ago
Which will result in a difference of squares? (negative 7 x + 4)(negative 7 x + 4) (negative 7 x + 4)(4 minus 7 x) (negative 7 x
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Answer:

(negative 7 x + 4)(negative 7 x minus 4)

Step-by-step explanation:

Consider two real numbers a and b. A difference of squares involving a and b is usually given as;

a^{2}-b^{2}

The difference of the two squares above can be factored to yield;

(a-b)(a+b)

This implies that in order to have the difference of squares we must have a product involving the difference and the sum of the numbers.

The expression;

(negative 7 x + 4)(negative 7 x minus 4) can also be written as ( 4 - 7x) ( -4 - 7x)

( 4 - 7x) ( -4 - 7x) = ( 4 - 7x) (-1( 4 + 7x)) = -1 *( 4 - 7x) ( 4 + 7x)

Expanding the last expression yields;

-1 (16 + 28x -28x - 49x^2) = -1 (16 - 49x^2) = 49x^2 - 16 which is in deed a difference of squares

3 0
2 years ago
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A sequence has a common ratio of Three-halves and f(5) = 81. Which explicit formula represents the sequence? f(x) = 24(Three-hal
Ede4ka [16]

Answer:

f(x)=16\, (\frac{3}{2} )^{x-1}

Step-by-step explanation:

Since we are given the common ratio (3/2), all we need to find to define the geometric sequence, is its multiplicative factor (a) that corresponds to the first term of the sequence - remember that all consecutive terms will be generated by multiplying this first value repeatedly by the common ratio (3/2) as shown below:  

f(1)=a\\f(2)=a\,*\,(\frac{3}{2} )\\f(3)=a\,*\,(\frac{3}{2} )^2\\f(4)=a\,*\,(\frac{3}{2} )^3\\f(5)=a\,*\,(\frac{3}{2} )^4

Since we are given the information that f(5)=81 we can use this to find the value of the first term:

f(5)=\,a\,*\,(\frac{3}{2} )^4\\81=\,a\,*(\frac{81}{16} )\\a\,*\,81=\,81\.*\,16\\a\,=\,16

Notice as well that the first term doesn't contain the common ratio, the second term contains the common ration (3/2) to the power one, the third one contains the common ratio to the power two, the fourth one contains it to the power three, and so forth. So the exponent at which the common ratio appears is always one unit less than the order (x) of the term in question. This concept helps us finalize the expression for the sequence's formula:

f(x)=16\,*\,(\frac{3}{2} )^{x-1}

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2 years ago
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