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Deffense [45]
2 years ago
3

The probability of drawing two red balls from a jar at random without replacement is 310 . The probability of drawing a red ball

first is 916 . What is the probability of drawing a second red ball, given that the first ball drawn was red?
Mathematics
2 answers:
Ugo [173]2 years ago
5 0

Answer:

8/15

Step-by-step explanation:

I just took the quiz

lawyer [7]2 years ago
4 0
Drawing a first red ball: A
Drawing a second red ball: B

Probability of drawing two red balls: P(A ∩ B)=0.310
Probability of drawing a red ball first: P(A)=0.916
Probability of drawing a second red ball given that the first ball drawn was red: P(B\A)=?

P(B\A)=P(A ∩ B) P(A)→
P(B\A)=(0.310)(0.916)→
P(B\A)=0.28396→
P(B\A)=0.284

Answer: T<span>he probability of drawing a second red ball, given that the first ball drawn was red is 0.284</span>
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Answer:

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Step-by-step explanation:

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The positive difference between the two roots of the quadratic equation $3x^2 - 7x - 8 = 0$ can be written as $\frac{\sqrt{m}}{n
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3x² - 7x - 8 = 0

We're asked about square roots so we won't try to factor; we'll go right for the quadratic formula,

x = ( 7 ± √(7² - 4(3)(-8))    )/(2(3)) = (7 ± √(49+96))/6 = 7/6 ± √145/6

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