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2 years ago

What is next letter BE GJ LO QT

1 answer:

3 0

<span>The letters BE GJ LO QT forms a sequence in which the first letter of each term is formed by counting five alphabets from the first letter of the preceding term while the last letter of each term is also formed by counting five alphabets from the last letter of the preceding term. Therefore, the next term in the sequence is VY.</span>

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Two shipments of components were received by a factory and stored in two separate bins. Shipment I has 2% of its contents defe

leva [86]

<h2>Answer:</h2>

The probability that a defective component came from shipment II is:

$0.7143\ or\ 71.43\%$

<h2>Step-by-step explanation:</h2>

Let A denote the event that the defective component was from shipment I

Also, P(A)=2%=0.02

and B denote the event that the defective component was from shipment II.

i.e. P(B)=5%=0.05

Also, P(shipment I is chosen)=1/2=0.5

and P(shipment II is chosen)=1/2=0.5

The probability that a defective component came from shipment II is calculated by Baye's rule as follows:

$=\dfrac{\dfrac{1}{2}\times 0.05}{\dfrac{1}{2}\times 0.02+\dfrac{1}{2}\times 0.05}}\\\\\\=\dfrac{0.05}{0.07}\\\\=\dfrac{5}{7}\\\\=0.7143\ or\ 71.43\%$

Hence, the answer is:

$0.7143\ or\ 71.43\%$

6 0

2 years ago

Dividends Per Share Seventy-Two Inc., a developer of radiology equipment, has stock outstanding as follows: 60,000 shares of cum

anygoal [31]

Answer and Step-by-step explanation:

The computation of dividends per share on each class of stock for each of the four years is shown below:-

Particulars 1st year 2nd-year 3rd-year 4th year

Preferred dividend

paid a $34,000 $38,000 $36,000 $36,000

Number of preferred

stock b 60,000 60,000 60,000 60,000

Dividend per share

(a ÷ b) $0.57 $0.63 $0.60 $0.60

Dividend paid to common

stockholders c $0 $38,000 $44,000 $64,000

Number of common stock

shares d 410,000 410,000 410,000 410,000

Dividend per share

on common stock $0 $0.093 $0.11 $0.16

(c ÷ d)

Working note:

Preferred dividend = Number of preferred stock shares × Par value per share × Percentage of dividend

= 60,000 × $20 × 3%

= $36,000

Preferred stock

For 1st year

= $34,000

For 2nd-year

Dividend in year 2+ Dividend balance in year 1

= $36,000 + ($36,000 - $34,000)

= $38,000

For 3rd-year

= $36,000

For 4th year

= $36,000

Common stock dividend

Particulars 1 year 2 year 3 year 4 year

Total dividend paid $34,000 $76,000 $80,000 $100,000

Less:

Preferred stock

dividend $34,000 $38,000 $36,000 $36,000

Dividend paid to common

stockholders $0 $38,000 $44,000 $64,000

8 0

2 years ago

Using Normal Distribution to Analyze Data Martin suspects that people carry less cash with them than they used to because of cre

jek_recluse [69]

Answer:

Step-by-step explanation:

Sample size = 95

X=cash carried by the persons

x bar = 8.00

s = sample std dev = 2.50

Std error = $\frac{s}{\sqrt{n} } =\frac{2.5}{\sqrt{95} } \\=0.2565$

Hence Z score would be

$\frac{x-8}{0.2565}$

$a) P(X$

-0.00

b) $P(9$

c) 95% conf interval margin of error = ± $1.96*0.2565$

=±0.54782

Confi interval = (8-0.5027, 8+0.5027)

= (7.4923, 8.5027)

C)If conf level increases, then width of interval would increase since critical value would increase.

If sample size increases std error would decrease and hence margin of error.

So interval would decrease.

3 0

1 year ago

At a financial institution, a fraud detection system identifies suspicious transactions and sends them to a specialist for revie

labwork [276]

Answer:

a. E(X) = 54.4

b. E(X) = 2.5

c. P(Y=2) = .0116

Step-by-step explanation:

E(X) = np = .40 probability * 136 trials = 54.4 blocked transmissions

To get the expected value, we simply multiply probability times number of trials. You can look at it in simple terms by thinking if there's a 50% chance of flipping heads and you flip a coin twice, in an ideal world you will have .5*2 = 1 head.

i. Let X represent the number of suspicious transmissions reviewed until finding the first blocked one. We will use a geometric distribution to model the "first" transmission. Whenever we're looking for the "first" time something happens, we use geometric.

ii. E(X) = 1/p , according to the geometric model.

= 1/.4 = 2.5.

We expect that the specialist will review 2.5 suspicious transactions <em>on average </em>before finding the first transmission that will be blocked.

i. Let Y represent the exact number of blocked transmissions out of 10. We will use a binomial distribution to model the "fixed" number of transmissions. Whenever we're looking for a "fixed" number of times something happens, we use binomial.

ii. P(Y=k) = (n choose k)(p^k)(q^n-k)

P(Y=2) = (¹⁰₂)(.4^2)(.6^10-2)

= 45 (.4^2)(.6^10-2) = .0016

As for calculator notation, the n choose k can be accessed on a TI-84 via MATH -> PRB -> nCr. It looks like 10 nCr 2 on the display.

Hence the probability that two transactions out of ten will be blocked is .0016 by the binomial model.

5 0

2 years ago

There were 200 members at a skating club. After some new members went in, there were 256 members altogether at the skating club.

mojhsa [17]

If I think I’m understanding it, the new members out of the 200 original would be adding 28% to the mix

4 0

1 year ago