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docker41 [41]
2 years ago
11

Keeping the properties of exponents in mind, to what power must you raise the expression 7 1/2 to get 7 as a result

Mathematics
1 answer:
zhenek [66]2 years ago
7 0
For this case we have the following expression:
 7 ^ {(1/2)}

 Rewriting the expression we have:
 (7 ^ {(1/2)}) ^ x

 Where,
 x: exponent to which we must raise the expression to obtain 7 as a result.
 We have then:
 7 ^ {((1/2) x)}

 The exponent must be equal to 1:
 (1/2) x = 1

 Clearing x we have: 
 x = 2

 Substituting valres:
 7 ^ {((1/2) 2)}

7 ^ 1

7
 Answer:
 
you must raise the expression to 2
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Sheet metal costs <u>$20</u> per square foot.

Step-by-step explanation:

7.6x - 2.3x = 106

We are finding the value of x.

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Divide both sides by 5.3.

x = 106 ÷ 5.3

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46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

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And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that p = 0.8.

10 students, so n = 10

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P(X \geq 9) = P(X = 9) + P(X = 10)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684

P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074

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0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that p = 0.3758

Two groups, so n = 2

We have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691

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