Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
Step-by-step explanation:
(A).Two corresponding sides of the given figures will be,
AB and DE
BC and EF
Similarly one pair of corresponding points will be,
A and D.
(B). Since large figure has been scaled to the smaller image,
Scale factor = 
= 
= 
= 0.25
Therefore, scale factor will be 0.25.
Answer:
The height of the baseball is 35 feet at the moment the player begins to leap.
Given:
5 bonds of face value of 1,000 that paid 5% annual interest rate.
5 bonds x 1,000 = 5,000
5,000 x 5% x 1 year = 250
The total annual interest income of James is 250. Each bond earns 50 per annum.
<span>An oblong box has a volume equal to lwh, where l is the length, w is the width, and h is the height. If the volume is 24 cubic feet, solve for the height in terms of the other sides.
Given:
volume of 24 cubic feet
Required:
height
Solution:
V = 24 cubic feet
assume that the length, weight and height of the box are all equal
so l = w = h
24 = l^3
l = 2.88 feet</span>