For the answer to the question above, the opposite angles at the intersection of two straight lines as shown in the graph are congruent.
So the answer is simply∡ EIA and ∡ KIJ are congruent.
I hope my answer helped you. Have a nice day!
Answer:
mCEA = 90ᴼ because CEA is a right angle, and right angles have 90ᴼ measures.
CEF is a straight angle because there are two 90ᴼ angles (CEA and AEF) and therefore there is 180ᴼ in total. A straight line has a measure of 180ᴼ.
AEF is a right angle because if CEA is a right angle and CEF is a straight line, then AEF has to be a right angle.
Answer:
Step-by-step explanation:
Hello!
Given the linear regression of Y: "Annual salary" as a function of X: "Mean score on teaching evaluation" of a population of university professors. It is desired to study whether student evaluations are related to salaries.
The population equation line is
E(Y)= β₀ + β₁X
Using the information of a n= 100 sample, the following data was calculated:
R²= 0.23
Coefficient Standard Error
Intercept 25675.5 11393
x 5321 2119
The estimated equation is
^Y= 25675.5 + 5321X
Now if the interest is to test if the teaching evaluation affects the proffesor's annual salary, the hypotheses are:
H₀: β = 0
H₁: β ≠ 0
There are two statistic you can use to make this test, a Student's t or an ANOVA F.
Since you have information about the estimation of β you can calculate the two tailed t test using the formula:
~
= 25.1109
The p-value is two-tailed, and is the probability of getting a value as extreme as the calculated
under the distribution 
p-value < 0.00001
I hope it helps!
Let us say that the intersection point of lines
AB and CD is called point E. The lines AB and CD are perpendicular to each
other which also means that the triangle CEB is a right triangle.
Where the line CB is the radius of the circle
while the side lengths are half of the whole line segment:
EB = 0.5 AB = 0.5 (8 ft) = 4 ft
CE = 0.5 CD = 0.5 (6 ft) = 3 ft
Now using the hypotenuse formula since the
triangle is right triangle, we can find for the radius or line CB:
CB^2 = EB^2 + CE^2
CB^2 = (4 ft)^2 + (3 ft)^2
CB^2 = 16 ft^2 + 9 ft^2
CB^2 = 25 ft^2
<span>CB = 5 ft = radius</span>