Bluetooth is a common wireless protocol used to make pan connections. <br> a. True <br> b. False

A user complains that her computer is performing slowly. She tells you the problem started about a week ago when new database so

k0ka [10]

Answer:

Option (B) is the correct of this question.

Explanation:

The performance of a monitor and process counters to observe the performance is the tool or method which determines the new software is hogging the computer resources. So this way the user don't have any problem with computer.

You can view log files in Windows Performance Monitor to see a visual representation of the performance counter data.
Performance counters are bits of code that log, count, and measure software events that allow a high-level view of user trends.
To customize the tracking of AD FS output using the Quality Monitor.
Type Output Monitor on Start screen, then click ENTER.
Expand Data Collector Sets in the console tree, right-click on User Specified, point to New, then select Data Collector Collection.

Other options are incorrect according to the given scenario.

4 0

2 years ago

Create a program named Auction that allows a user to enter an amount bid on an online auction item. Include three overloaded met

Olin [163]

Answer:

Explanation:

The following code is written in Java and creates the overloaded methods as requested. It has been tested and is working without bugs. The test cases are shown in the first red square within the main method and the output results are shown in the bottom red square...

class Auction {

public static void main(String[] args) {

bid(10);

bid(10.00);

bid("10 dollars");

bid("$10");

bid("150 bills");

}

public static void bid(int bid) {

if(bid >= 10) {

System.out.println("Bid Accepted");

} else {

System.out.println("Bid not high enough");

}

public static void bid(double bid) {

if(bid >= 10) {

System.out.println("Bid Accepted");

} else {

System.out.println("Bid not high enough");

}

public static void bid(String bid) {

if (bid.charAt(0) == '$') {

if (Integer.parseInt(bid.substring(1, bid.length())) > 0) {

System.out.println("Bid Accepted");

return;

} else {

System.out.println("Bid not in correct Format");

return;

}

int dollarStartingPoint = 0;

for (int x = 0; x < bid.length(); x++) {

if (bid.charAt(x) == 'd') {

if (bid.substring(x, x + 7).equals("dollars")) {

dollarStartingPoint = x;

} else {

break;

}

if (dollarStartingPoint > 1) {

if (Integer.parseInt(bid.substring(0, dollarStartingPoint-1)) > 0) {

System.out.println("Bid Accepted");

return;

} else {

System.out.println("Bid not in correct format");

return;

}

} else {

System.out.println("Bid not in correct format");

return;

}

3 0

1 year ago

The domains of the risk IT framework mutually inform each other, creating flexibility and agility. It is possible to uncover a p

Andrej [43]

Answer:

The best option is A).True

Explanation:

This is because, according to the statement, it is possible to uncover a potential threat in the risk governance domain and quickly assess its impact using the risk evaluation domain in an IT environment. The risk IT framework is used in an IT environment for security of domains, the business involved, etc.

6 0

2 years ago

This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance

aleksandr82 [10.1K]

Answer:

Question Options :

(1) Prompt the user to input five pairs of numbers: A player’s jersey number (0 – 99) and the player’s rating (1 – 9). Store the jersey numbers in one int array and the ratings in another int array. Output these array(i.e., output the roster).

(2) Implement a menu of options for a user to modify the roster. Each option is represented by a single character. The program initially outputs the menu, and outputs the menu after a user chooses an option. The program ends when the user chooses the option to Quit. For this step, the other options do nothing. (2 pt)

(3) Implement the “Output roster” menu option. (1 pt)

(4) Implement the “Add player” menu option. Prompt the user for a new player’s jersey number and rating. Append the values to the two arrays. (1 pt)

(5) Implement the “Delete player” menu option. Prompt the user for a player’s jersey number. Remove the player from the roster (delete the jersey number and rating). (2 pts)

(6) Implement the “Update player rating” menu option. Prompt the user for a player’s jersey number. Prompt again for a new rating for the player, and then change that player’s rating. (1 pt)

(7) Implement the “Output players above a rating” menu option. Prompt the user for a rating. Print the jersey number and rating for all players with ratings above the entered value. (2 pts)

/******************************************************************************

This program will store roster and rating information for a soccer team.

*******************************************************************************/

#include <iostream>

#include <vector>

using namespace std;

int main() {

vector< int> jerseyNumber;

vector< int> rating;

int temp;

for (int i = 1; i <= 5; i++) {

cout << "\nEnter player " << i << "'s jersey number: ";

cin >> temp;

if ((temp >= 0) && (temp <= 99)){

jerseyNumber.push_back(temp);}

cout << "Enter player " << i << "'s rating: ";

cin >> temp;

if ((temp >= 0) && (temp <= 9)){

rating.push_back(temp);}

cout << endl;

} cout << endl;

cout << "ROSTER" << endl;

for (int i = 0; i < 5; i++)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i) << ", Rating: " << rating.at(i) << endl;

char option;

while (true) {

cout << endl;

cout << "MENU" << endl;

cout << "a - Add player" << endl;

cout << "d - Remove player" << endl;

cout << "u - Update player rating" << endl;

cout << "r - Output players above a rating" << endl;

cout << "o - Output roster" << endl;

cout << "q - Quit" << endl << endl;

cout << "Choose an option: " << endl;

cin >> option;

switch (option) {

case 'a':

case 'A':

cout << "Enter another player's jersey number: " << endl;

cin >> temp;

if ((temp >= 0) && (temp <= 99)){

jerseyNumber.push_back(temp);}

cout << "Enter another player's rating: " << endl;

cin >> temp;

if ((temp >= 0) && (temp <= 9)){

rating.push_back(temp);}

break;

case 'd':

case 'D':

cout << "Enter a jersey number: ";

cin >> temp;

for (int i = 0; i < jerseyNumber.size(); i++) {

if (jerseyNumber.at(i) == temp) {

jerseyNumber.erase(jerseyNumber.begin() + i);

rating.erase(rating.begin() + i);

break; }

} break;

case 'u':

case 'U':

cout << "Enter a jersey number: ";

cin >> temp;

for (int i = 0; i < jerseyNumber.size(); i++) {

if (jerseyNumber.at(i) == temp) {

cout << "Enter a new rating " << "for player: ";

cin >> temp;

rating.at(i) = temp;

break; }

} break;

case 'r':

case 'R':

cout << "Enter a rating: ";

cin >> temp;

cout << "\nABOVE " << temp << endl;

for (int i = 0; i < jerseyNumber.size(); i++)

if (rating.at(i) > temp)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

<< ", Rating: " << rating.at(i) << endl;

break;

case 'o':

case 'O':

cout << "ROSTER" << endl;

for (int i = 0; i < jerseyNumber.size(); i++)

cout << "Player " << i + 1 << " -- " << "Jersey number: " << jerseyNumber.at(i)

<< ", Rating: " << rating.at(i) << endl;

break;

case 'q':

return 0;

default: cout << "Invalid menu option." << " Try again." << endl;

}

Explanation:

6 0

2 years ago

For the (pseudo) assembly code below, replace X, Y, P, and Q with the smallest set of instructions to save/restore values on the

Dimas [21]

Answer:

Explanation:

Let us first consider the procedure procA; the caller in the example given.

Some results: $s0,$s1,$s2, $t0,$t1 and $t2 are being stored by procA. Out of these registers, few registers are accessing by procA after a call to procB. But, procB might over-write these registers.

Thus, procA need to save some registers into stack first before calling procB, .

only $s1,$t0 and $t1 are being used after return from procB in the given example,

Caller saves and restores only values in $t0-$t9, according to MIPS guidelines for caller-saved and callee-saved registers, .

Thus, procA needs to save only $t0 and $t1.

jal instruction overwrites the register $ra by writing the address, to which the control should jump back, after completing the instructions of procB, when procB is called,.

Therefore, procA also need to save $ra into stack.

ProcA is writing new values into $a0,$a2, procA must save $a0 and $a1 first before calling procB, .

In the given example, after return from procB, only $a0 is being used. It is therefore enough to save $a0.

Also, procA needs to save frame pointer, which points the start of the stack space for each procedure.

Generally, as soon as the procedure begins, frame pointer is set to the current value of the stack pointer,.

Let us consider the procedure procB; the callee in the given example.

The callee is responsible for saving values in $s0-$s7 and restoring them before returning to caller, this is according to MIPS guidelines for caller-saved and callee-saved registers,

procB is expected to over-write the registers $s2 and $t0. Nonetheless, in the first two lines, procB might over-write the registers $s0 and $s1.

Thus, procB is responsible for saving and restoring $s0,$s1 and $s2.

X:

We need to create space for 5 values on the stack since procA needs to save $a0,$ra,$t0,$t1 and $fp(frame pointer), . Each value(word) takes 4 bytes.

$sp = $sp – 20 # on the stack, create space for 5 values

sw $a0, 16($sp) # store the result in $a0 into the memory address

# indicated by $sp+20

sw $ra, 12($sp) # save the second value on stack

sw $t0, 8($sp) # save the third value on stack

sw $t1, 4($sp) # save the fourth value on stack

sw $fp, 0($sp) # To the stack pointer, save the frame pointer

$fp = $sp # To the stack pointer, set the frame pointer

Y:

lw $fp, 0($sp) # from stack, start restoring values

lw $t1, 4($sp)

lw $t0, 8($sp)

lw $ra, 12($sp)

lw $a0, 16($sp)

$sp = $sp + 20 # decrease the size of the stack

P:

$sp = $sp – 12 # for three values, create space on the stack

sw $s0, 0($sp) # save the value in $s0

sw $s1, 0($sp) # save the value in $s1

sw $s2, 0($sp) # save the value in $s2

Q:

lw $s0, 0($sp) # from the stack, restore the value of $s0

lw $s1, 0($sp) # from the stack, restore the value of $s1

lw $s2, 0($sp) # from the stack, restore the value of $s2

$sp = $sp + 12 # decrease the stack size

8 0

2 years ago

Bluetooth is a common wireless protocol used to make pan connections. a. True b. False