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2 years ago

Please help apex ansers

Mathematics

1 answer:

goblinko [34]2 years ago

6 0

The factorization of A is y = (x - 8)(x + 7).
The factorization of B is y = (x + 1)(x - 4)(x - 5)

In order to find these, you must first find where each graph crosses the x-axis. In the first problem it does so at 8 and -7. In order to find the correct parenthesis for those, you need to write it out as a statement and then solve for 0.

x = 8 ---> subtract 8 from both sides
x - 8 = 0
This means we use (x - 8) in our factorization.

You then need to repeat the process until you have all the pieces. In the second problem, there will be 3 instead of 2 since it crosses the axis 3 times.

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Claire for to a show sale. Everything on the shelf is 35% off the marked price. She falls in love with a pair of red heels that

lyudmila [28]

Percentage of discount on the Marked price = 35%
Marked price of the pair of red heels that Claire falls in love with = $64.99
Then
Amount of discount on the
marked price of the pair of red heels = (35/100) * 64.99 dollars
   = 0.35 * 64.99 dollars
   = 22.746 dollars
   = 22.75 dollars
Then
Price of the red heels after discount = (64.99 - 22.75) dollars
   = 42.24 dollars
Percentage of sales tax that needs to be given by Claire = 7.5%
Amount of sales tax that needs to be given by Claire = (7.5/100) * 42.24 dollars
   = 316.80/100 dollars
   = 3.168 dollars
   = 3.17 dollars
Then
The total price of the
red heels that Claire has to pay = (42.24 + 3.17) dollars
   = 45.41 dollars
So Claire has to pay a total of $45.41 for the pair of red heels she has fallen in love with.

8 0

2 years ago

Which of the following is the expansion of (3c + d2)6?

vovangra [49]

Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

on applying binomial theorem, $(a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r$

Here a=3c, $b=d^2$ and n=6,

Thus, $(3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r$

⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

⇒ $(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}$

⇒ $(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$

3 0

2 years ago

Read 2 more answers

HELP PLEASE. Which regression equation best fits these data?

AlladinOne [14]

Answer:

B. y = -0.58x^2 -0.43x +15.75

Step-by-step explanation:

The data has a shape roughly that of a parabola opening downward. So, you'll be looking for a 2nd-degree equation with a negative coefficient of x^2. There is only one of those, and its y-intercept (15.75) is in about the right place.

The second choice is appropriate.

_____

The other choices are ...

A. a parabola opening upward

C. an exponential function decaying toward zero on the right and tending toward infinity on the left

D. a line with negative slope (This might be a good linear regression model, but the 2nd-degree model is a better fit.)

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2 years ago

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Show a way to count from 170 to 410 using tens and hundreds. circle at least 1 benchmark number

Anastasy [175]

Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.

The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.

6 0

2 years ago

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Patrick owns an apartment building. He knows that the money he earns in a month depends on the rent he charges. The relationship

belka [17]

E=13,000 andE=1/50R(1650-R)

0.02R(1650-R)=13000

(0.02R)(1650)-0.02R²=13000

0.02R²-33R+13000=0

R2-1650R+650000=0

SOLVE W QUAD FORMULA

7 0

2 years ago