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2 years ago

14

15. Product A is an 8 oz. bottle of cough medication that sells for $1.36. Product B is a 16 oz. bottle of cough medication that

costs $3.20. Which product has the lower unit price and how do you determine the answer

1 answer:

Sever21 [200]2 years ago

7 0

To determine unit price, you must find the price per 1 oz. So, divide 1.36 by 8 and divide 3.2 by 16.
1.36/8=.17
3.2/16=.2
Product A has the lower unit price because .17 is less than .2.

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Solve the recurrence relation: hn = 5hn−1 − 6hn−2 − 4hn−3 + 8hn−4 with initial values h0 = 0, h1 = 1, h2 = 1, and h3 = 2 using (

musickatia [10]

(a) Suppose $h_n=r^n$ is a solution for this recurrence, with $r\neq0$ . Then

$r^n=5r^{n-1}-6r^{n-2}-4r^{n-3}+8r^{n-4}$
$\implies1=\dfrac5r-\dfrac6{r^2}-\dfrac4{r^3}+\dfrac8{r^4}$
$\implies r^4-5r^3+6r^2+4r-8=0$
$\implies (r-2)^3(r+1)=0\implies r=2,r=-1$

So we expect a general solution of the form

$h_n=c_1(-1)^n+(c_2+c_3n+c_4n^2)2^n$

With $h_0=0,h_1=1,h_2=1,h_3=2$ , we get four equations in four unknowns:

$\begin{cases}c_1+c_2=0\\-c_1+2c_2+2c_3+2c_4=1\\c_1+4c_2+8c_3+16c_4=1\\-c_1+8c_2+24c_3+72c_4=2\end{cases}\implies c_1=-\dfrac8{27},c_2=\dfrac8{27},c_3=\dfrac7{72},c_4=-\dfrac1{24}$

So the particular solution to the recurrence is

$h_n=-\dfrac8{27}(-1)^n+\left(\dfrac8{27}+\dfrac{7n}{72}-\dfrac{n^2}{24}\right)2^n$

(b) Let $G(x)=\displaystyle\sum_{n\ge0}h_nx^n$ be the generating function for $h_n$ . Multiply both sides of the recurrence by $x^n$ and sum over all $n\ge4$ .

$\displaystyle\sum_{n\ge4}h_nx^n=5\sum_{n\ge4}h_{n-1}x^n-6\sum_{n\ge4}h_{n-2}x^n-4\sum_{n\ge4}h_{n-3}x^n+8\sum_{n\ge4}h_{n-4}x^n$
$\displaystyle\sum_{n\ge4}h_nx^n=5x\sum_{n\ge3}h_nx^n-6x^2\sum_{n\ge2}h_nx^n-4x^3\sum_{n\ge1}h_nx^n+8x^4\sum_{n\ge0}h_nx^n$
$G(x)-h_0-h_1x-h_2x^2-h_3x^3=5x(G(x)-h_0-h_1x-h_2x^2)-6x^2(G(x)-h_0-h_1x)-4x^3(G(x)-h_0)+8x^4G(x)$
$G(x)-x-x^2-2x^3=5x(G(x)-x-x^2)-6x^2(G(x)-x)-4x^3G(x)+8x^4G(x)$
$(1-5x+6x^2+4x^3-8x^4)G(x)=x-4x^2+3x^3$
$G(x)=\dfrac{x-4x^2+3x^3}{1-5x+6x^2+4x^3-8x^4}$
$G(x)=\dfrac{17}{108}\dfrac1{1-2x}+\dfrac29\dfrac1{(1-2x)^2}-\dfrac1{12}\dfrac1{(1-2x)^3}-\dfrac8{27}\dfrac1{1+x}$

From here you would write each term as a power series (easy enough, since they're all geometric or derived from a geometric series), combine the series into one, and the solution to the recurrence will be the coefficient of $x^n$ , ideally matching the solution found in part (a).

3 0

2 years ago

What is the greatest common factor of 4k, 18k4, and 12?

Semenov [28]

The greatest common factor of 4k, 18k4 and 12 is
4

Finding the GCF of monomials requires inspection of the terms and looking for common factors that would be able to reduce the terms to whole numbers and variables with positive exponents.

5 0

2 years ago

Read 2 more answers

The amount of profit, p, you earn by selling knives, k, can be determined by: p=200k-500 a) Determine the constraints on profit

Natalka [10]

We are given with the formula
p = 200k - 500
a) The constraint for this formula is obtained from the idea that the profit must be positive
200k - 500 > 0
k > 500/200
k > 2.5
b) To make 14000 profit
14000 = 200k - 500
k = 72.5 or 73 knives must be sold

3 0

2 years ago

200 students attend a school which offers French and History. 10% of those who take History also take French and 4 times as many

SIZIF [17.4K]

Answer: P(hist& french)=16/200=0.08

Step-by-step explanation:

To find the required probability we have to know what is the number of students that take both History and French ( Intersection of 2 circles in Venn diagram)

1. Lets find the number of students that take History or French or both.

We know that 8% from 200 take neither History or French. So number or students who take History or French or both is 200-200*0.08=184

2. Let number of students that takes French (or both Fr+Hist)=x (left circle)

So number of students that takes History (or both Fr+Hist)=4x (right circle)

So number of students that take both French+History= 10% from 4x or

0.1*4x=0.4x (circles' intersection)

3. Now we have the equation as follows:

x+4*x-0.4*x = 184

4.6*x=184

x=40 students takes French (or both French+ History)

4*x= 40*4=160 students takes History (or both French+ History)

10% from 160 =0.1*160=16 students takes both History and French

P(hist& french)=16/200=0.08

7 0

2 years ago

At the start of 2014, Mike's car is worth 12000. the car depreciates by 30 percent every year. how much is his car worth in 2017

Anarel [89]

Answer:

$4,116

Step-by-step explanation:

Worth of Mike's car at the start of 2014 = $12,000

If the car is said to depreciates every year by 30% = 30/100 = 0.3

The worth of the car at the start of 2017 is what we are to determine.

This means that the car depreciated by 30% (0.3) for 3 years since 2014 (2017 - 2014 = 3 yrs)

The worth at the start of 2017 would be calculated as follows:

12,000 × (1 - 0.3)³

= 12,000 × (0.7)³

= 12,000 × 0.343

= 4,116

Worth of the car at the start of 2017 would be $4,116

4 0

2 years ago