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motikmotik
2 years ago
3

Solve for x. 5(x-10)=30-15x

Mathematics
2 answers:
dlinn [17]2 years ago
8 0
<span>5(x-10)=30-15x
Expand by using distributive property
5x - 50 = 30 - 15x
Add 15x to both sides
</span>5x - 50 + 15x = 30 - 15x + 15x
Combine like terms and simplify
20x - 50 = 30
Add 50 to both sides
20x - 50 + 50 = 30 + 50
Simplify
20x = 80
Divide both sides by 20
20x / 20 = 80/20
Simplify
x = 4

Answer
B. second option
x = 4

zepelin [54]2 years ago
3 0
The answer would be x=4
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The graph of f(x) = x2 is translated to form g(x) = (x – 5)2 + 1. On a coordinate plane, a parabola, labeled f of x, opens up. I
Lostsunrise [7]

Answer:

The option which is:

On a coordinate plane, a parabola opens up. It goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10).

Step-by-step explanation:

At first we should know the rules of translation

1) {f(x) + a} is f(x) shifted up (a) units

2) {f(x) – a} is f(x) shifted down (a) units

3) {f(x + a)} is f(x) shifted left (a) units.

4) {f(x – a)} is f(x) shifted right (a) units.

Given:

f(x) = x²

g(x) = (x-5)² + 1

By comparing [ the translation from f(x) to g(x) ] with the rules of translation

We can deduce that g(x) is the image of f(x) by translation 5 units right and 1 unit up ( rules 1 and 4)

See the attached figure which represent the graph of f(x) and g(x)

As shown g(x) goes through (2, 10), has a vertex at (5, 1), and goes through (8, 10)

3 0
2 years ago
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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

substitute the value of h to find the area

A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

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2 years ago
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Answer:

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Step-by-step explanation: there is none

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2 years ago
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