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Dmitry [639]
2 years ago
8

A recipe calls for 1 part beans to 1-1/2 parts rice. If 1-1/2 parts of beans are used how much rice should be used

Mathematics
2 answers:
natima [27]2 years ago
8 0

Answer:

2\frac{1}{4}  part of rice should be used.

Step-by-step explanation:

A recipe calls for 1 part beans to 1\frac{1}{2} part rice.

If 1\frac{1}{2} parts of beans used,

rice should be = 1\frac{1}{2} × 1\frac{1}{2}

                         = \frac{3}{2} × \frac{3}{2}  

                         = \frac{9}{4}                              

                         = 2\frac{1}{4} part or 2.25 parts rice

2\frac{1}{4}  part of rice should be used.

Maurinko [17]2 years ago
5 0
I think the answer is 2 parts rice. If you added half to the beans, do it to the rice too.
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Answer:

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Step-by-step explanation:

The problem statement tells you Owen can build up to 10 birdhouses, and that b represents that number. Then 0 ≤ b ≤ 10 is the domain described by the problem statement.

It also tells you that W(b) = 12b, so filling in values from 0 to 10 gives a range from 0 to 120: 0 ≤ W(b) ≤ 120.

These observations match choice D.

8 0
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Suzie is going on vacation and will need to rent a car. She has narrowed it down to two choices. Miller Car Rental charges a $99
Kay [80]

Answer: she would have to drive the quick cars car 160 miles (Fee is included) for it to add up to the Miller car rental car.

Step-by-step explanation:

4 0
2 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?
Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

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x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

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8 0
2 years ago
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On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc
Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

The amount of drug she received on the eleventh day = 29 mg

Therefore, we have an arithmetic progression with the formula for the nth term given as follows;

aₙ = a₁ + (n - 1)·d

Where;

a₁ = u1

n = The number of terms

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a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

b. For the eleventh day, the amount of drugs she receives, which is 29 milligrams, is given as follows;

a₁₁ = u1 + (11 - 1)·d = u1 + 10·d = 29

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29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

8 = 4·d

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21 = u1 + 12

21 - 12 = u1

∴ u1 = 9

d = 2, u1 = 9.

4 0
1 year ago
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Nostrana [21]
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The new prices are 5% increase from the original price. 

6 0
2 years ago
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