Answer:
θ∈{
}
Explanation:
The given equation is


Applying values on 'n' we obtain values of θ that beling to [0,2π)
For n=0, θ=
For n=1, θ =
For n=2,θ =
For n=3,θ =
We have that
using a graph tool--------------> graph the <span> cosecant function
</span>see the attached figure
the answer is the option B
First of all, a bit of theory: since the area of a square is given by

where s is the length of the square. So, if we invert this function we have
.
Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}
The answer is Two students are the same age but have different heights. Hope this helps!
In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m