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Citrus2011 [14]
2 years ago
10

Which expression can be used I find the difference of the polynomials (10m-6)-(7m-4)?

Mathematics
2 answers:
garik1379 [7]2 years ago
8 0

Hi!


To solve this, we can take away the parentheses.

10m-6-7m-4

Group like terms together

10m-7m-6-4

Simplify

3m-2


The answer is 3m-2


Hope this helps! :)

-Peredhel

Aleks04 [339]2 years ago
4 0

Answer: Hi! in this problem we have two polynomials; (10m -6) and (7m -4).

if we want to find the difference between these polynomials, we can do a direct subtraction.

so:

(10m - 6) - (7m - 4)

10m - 6 - 7m + 4

(10m - 6m) + (4 - 6)

3m -2

So the difference between the two polynomials is d = 3m - 2.

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Answer:

(a)\ 0.0864

(b)\ 0.096

(c)\ 0.24

(d)\ 0.936

Step-by-step explanation:

Given

p \to close

q \to fail to close

p = 60\%

p = 0.60

First, calculate the value of q

Using complement rule

q = 1 - p

q = 1 - 0.60

q = 0.40

So, we have:

p = 0.60 and q = 0.40

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

Pr = p*p*p*q

Pr = p^3*q

Pr = 0.60^3*0.40

Pr = 0.0864

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

Pr = q * q * p

Pr = q^2 * p

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Pr = 0.096

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

Pr = q * p

Pr = 0.40 * 0.60

Pr = 0.24

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

Pr = q*q*q

Pr = q^3

The opposite is that the first he closes is one of the first three

So, we have:

Pr' = 1- Pr --- complement rule

Pr' = 1- q^3

Pr' = 1- 0.40^3

Pr' = 1- 0.064

Pr' = 0.936

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Answer:

Step-by-step explanation:

Given is a triangle RST and another triangle R'S'T' tranformed from RST

Vertices of RST are (0, 0), (negative 2, 3), (negative 3, 1).

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Now reflected on the line y=0 i.e. x axis

New vertices are

(2,0) (0,-3) (-1,-1)

8 0
2 years ago
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