Question

A) Point M is chosen random inside the big circle The radii of the small, middle and big circles are 4 cm, 7 cm, 10 cm respectively. What is the probability that Point M will be in part A?
B) Point M is chosen randomly inside the big circle The radii of the small, middle and big circles are 4 cm, 7 cm, 10 cm respectively. What is the probability that Point M will be in part B?
C) Point M is chosen randomly inside the big circle The radii of the small, middle and big circles are 4 cm, 7 cm, 10 cm respectively. What is the probability that
Point M will be in part C?

Answer 1

The missing image for this question is attached below.

Area of circle = πr²

Question 1st)

The probability that the a point chosen at random will be in part A will be equal to = (Area of Part A) / (Total Area)

Area of Part A = Area of Big Circle - Area of Middle Circle

So, Area of Part A = 100π - 49π = 51π

Total Area = Area of Big Circle = 100π

Thus, the probability that the point is in Part A = $\frac{51\pi}{100\pi} =0.51$

Question 2nd)

The probability that the a point chosen at random will be in part B will be equal to = (Area of Part B) / (Total Area)

Area of Part B = Area of Middle Circle - Area of Smaller Circle

So, Area of Part B = 49π - 16π = 33 π

Total Area = Area of Big Circle = 100π

Thus, the probability that the point is in Part B = $\frac{33\pi}{100\pi} =0.33$

Question 3rd:

The probability that the a point chosen at random will be in part C will be equal to = (Area of Part C) / (Total Area)

Area of Part C = Area of Small Circle

So, Area of Part C = 16π

Total Area = Area of Big Circle = 100π

Thus, the probability that the point is in Part C = $\frac{16\pi}{100\pi}=0.16$