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maria [59]
2 years ago
6

Identify the property used in each step of solving the inequality 3x – 2 > –4.

Mathematics
2 answers:
cestrela7 [59]2 years ago
8 0

Answer:

Addition Property and Multiplication Property

Step-by-step explanation:

Marizza181 [45]2 years ago
7 0

Answer:addition and multiplication

Step-by-step explanation:

I just did it

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Pedro works as a newspaper deliverer. He receives a base pay plus an additional amount per newspaper delivered. Last week, Pedro
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Answer is

<span>g(x) = 2.5x + 25

</span>5 newspapers, 2.5(5) + 25 = 12.5 + 25 = 37.5
20 newspapers, 2.5(20) + 25 = 50 + 25 = 75
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A researcher is studying psychological factors in academic achievement among teenage girls. One variable she is particularly int
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Answer:

The correct answer is:option A and B

Step-by-step explanation:

A researcher is studying and examining psychological factors in academic achievement amongst teenage boys. One of the variable he is particularly paying more attention is in determination.

The quantifying of variability for the variable determination suggests how stretched out are the values for determination amid teenage boys (do all boys that are still in their teenage years have the same determination) and how constant are the values of determination amid teenage boys.

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Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. Quotient Divisor x3 – 3x2 + x – 5 x x4 –3x3 x2 A – 1
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4 0
1 year ago
20 POINTS
TiliK225 [7]

Answer:

Step-by-step explanation:

There are <u>6</u><u> different shapes</u>

You want the outcome to be a Nonagon

You put the outcome as a ratio 1/6

1/6=0.1666667

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3 0
2 years ago
Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant
pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)

Applying the following property of exponentials numbers in (II):

e^{a}.e^{b}=e^{a+b}

Therefore e^{-28k} can be written as e^{-14k}.e^{-14k}

152=190-Ae^{-14k}.e^{14k}

Replacing (I) in the previous equation:

152=190-76e^{-14k}

Solving for k:

Subtracting 190 both sides, dividing by -76:

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Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

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A=152

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2 years ago
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