In each figure, a|| b . Determine whether the third figure is a translation image of the first figure. Write yes or no. Explain
your answer.
a. Yes; it is one reflection after another with respect to the two parallel lines.
b. No; it is a reflection followed by a translation.
c. No; it is a reflection followed by a rotation.
d. No; it is one reflection after another with respect to the two parallel lines.
a. Yes; it is one reflection after another with respect to the two parallel lines.
b. No; it is a reflection followed by a translation.
c. No; it is a reflection followed by a rotation.
d. No; it is one reflection after another with respect to the two parallel lines.
2 answers:
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First, note that for angles LMP and NMP you have
If is
more than
then
Now, since you have
Therefore,
Answer:
Answer:
2500 numbers
Step-by-step explanation:
Problem;
Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;
Let us approach this in a step wise manner;
5 -digits numbers ranges from 10,000 to 99,999
To solve this problem, let us find the number of digits that are divisible by 45;
the first number divisible by 45 within this range is 10035
the last number divisible by 45 in this range is 99990
increment is 45
The total number in this range is:
+ 1 =
+ 1
= 2000 numbers
To solve this problem, let us find the number of digits that are divisible by 60;
the first number divisible by 60 within this range is 10020
the last number divisible by in this range is 99960
increment is 60
The total number in this range is:
+ 1 =
+ 1
= 1500 numbers
To solve this problem, let us find the number of digits that are divisible by 90;
the first number divisible by 90 within this range is 10080
the last number divisible by in this range is 99990
increment is 90
The total number in this range is:
+ 1 =
+ 1
= 1000 numbers
Now solution:
Number of 5 digits = number of 45 + number of 60 - number of 90
= 2000 + 1500 - 1000
= 2500 numbers
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to 
.
---> equation (1)
By using pythagoras rule which states that the
---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
substitute this value in equation (1) then
where A is the area of the square whose side is x
By using pythagoras rule which states that the
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
where A is the area of the square whose side is x