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2 years ago

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The function c=15+9h represents the amount c ( in dollars) it will cost you for a one time lawn care service of h hours. Identif

y the independent and dependent variables. Is the domain discrete or continuous? Explain

1 answer:

Mandarinka [93]2 years ago

3 0

Answer:

see the procedure

Step-by-step explanation:

we know that

A <u><em>discrete domain</em></u> is a set of input values that consists of only certain numbers in an interval

A <u><em>continuous domain</em></u> is a set of input values that consists of all numbers in

an interval

In this problem we have

$c=15+9h$

where

c is the amount in dollars

h is the number of hours

The total cost c depends of the number of hours h

so

c is the dependent variable, and h is the independent variable

You cannot buy part of an hour, only a certain number of hours. Because h represents the number of hours, it must be a whole number.

So, the domain is 0, 1, 2, 3, 4, 5, ... it is discrete

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Oil flows back and forth between a small and large tank. When oil is moving into the large tank, the flow rate is

Vladimir [108]

Answer:

so the answer is =6187200

Step-by-step explanation:

600 divide by 4=150

150 multiply 32=4800

4800 divided by 1289=6187200.

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2 years ago

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Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of cracke

Anna11 [10]

Answer:

The cost of a box of crackers is $2.25.

Step-by-step explanation:

Let the cost of a containers of yogurt is $x and cost of a box of crackers is $y.

It is given that Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55.

$4x+3y=9.55$ .... (1)

She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90.

$2x+2y=5.90$ .... (2)

On solving (1) and (2), using graphing calculator, we get

$x=0.7$

$y=2.25$

Therefore the cost of a box of crackers is $2.25.

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2 years ago

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Find the equation of the plane through the point (2,5,7) that is parallel to the line r=(3i+2j−2k)+t(i+2j+9k) and perpendicular

insens350 [35]

The plane we want to find has general equation

$a(x-2)+b(y-5)+c(z-7)=0$

with $a,b,c$ not equal to 0, and has normal vector

$\vec n=a\,\vec\imath+b\,\vec\jmath+c\,\vec k$

$\vec n$ is perpendicular to both the normal vector of the other plane, which is $4\,\vec\imath+5\,\vec\jmath+6\,\vec k$ , as well as the tangent vector to the line $\vec r(t)$ , which is $\vec\imath+2\,\vec\jmath+9\,\vec k$ .

This means the dot product of $\vec n$ with either vector is 0, giving us

$\begin{cases}4a+5b+6c=0\\a+2b+9c=0\end{cases}$

Suppose we fix $c=1$ . Then the system reduces to

$\begin{cases}4a+5b=-6\\a+2b=-9\end{cases}$

and we get

$(4a+5b)-4(a+2b)=-6-4(-9)\implies-3b=30\implies b=-10$

$a+2(-10)=-9\implies a=11$

Then one equation for the plane could be

$\boxed{11(x-2)-10(y-5)+(z-7)=0}$

or in standard form,

$\boxed{11x-10y+z=-21}$

The solution is unique up to non-zero scalar multiplication, which is to say that any equation $(11x-10y+z)k=-21k$ would be a valid answer. For example, suppose we instead let $c=2$ ; then we would have found $a=22$ and $b=-20$ , but clearly dividing both sides of the equation

$22(x-2)-20(y-5)+2(z-7)=0$

by 2 gives the same equation as before.

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2 years ago

A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb

Kobotan [32]

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

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Solving the linear system above:

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2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

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2 years ago

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Sonja [21]

Well if there are 36 apples and there are 12 more apples then peaches then 36-12= 24 24/2=12

Answer=12

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