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Kisachek [45]
2 years ago
11

Oil flows back and forth between a small and large tank. When oil is moving into the large tank, the flow rate is

Mathematics
2 answers:
Vladimir [108]2 years ago
3 0

Answer:

so the answer is =6187200

Step-by-step explanation:

600 divide by 4=150

150 multiply 32=4800

4800 divided by 1289=6187200.

aleksandrvk [35]2 years ago
3 0

Answer:

✔ 128

into the  

✔ small

tank.

After the 32 minutes, how much oil is in the large tank?  

✔ 472

gallons

Step-by-step explanation: Just did it on Edge

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The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking
Anna [14]

Answer:

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 160, \pi = \frac{14}{160} = 0.088

88% confidence level

So \alpha = 0.12, z is the value of Z that has a pvalue of 1 - \frac{0.12}{2} = 0.94, so Z = 1.555.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 - 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.053

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 + 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.123

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

6 0
2 years ago
A 22.5 ounce candle burns at the rate of one ounce every 5 hours. write an equation for the amount of candle left
maks197457 [2]

Answer:

y = 22.5 - 0.2t

Step-by-step explanation:

Given;

total number of candle, n = 22.5 ounce

Rate of candle burn, R = 1 ounce per 5 hours  = \frac{1 \ ounce}{5 \ hours} = 0.2 \ \frac{ounce}{hour}

The amount of candle left = total initial value - amount burnt

let the amount let = y

y = 22.5 - 0.2t

where;

t is the time in which the candle is burnt

Thus, the equation for the amount of candle left is given by;

y = 22.5 - 0.2t

7 0
1 year ago
25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct
soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of 2\pi and a vertical compression.

Step-by-step explanation:

We are given the parent function as y= \cot x

It is given that, transformations are applied to the parent function in order to obtain the function y=0.5\cot (0.5x) i.e. y=\frac{1}{2}\cot (\frac{x}{2})

That is, we see that,

The parent function y= \cot x is stretched horizontally by the factor of \frac{1}{2} which gives the function y=\cot (\frac{x}{2}).

Further, the function is compressed vertically by the factor of \frac{1}{2} which gives the function y=\frac{1}{2}\cot (\frac{x}{2}).

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period \frac{P}{|b|}.

Since, the period of y= \cot x is \pi, so the period of y=\frac{1}{2}\cot (\frac{x}{2}) is \frac{\pi}{1/2} = 2\pi

Hence, we get option C is correct.

3 0
2 years ago
Convert the angle \theta=\dfrac{29\pi}{15}θ= 15 29π ​ theta, equals, start fraction, 29, pi, divided by, 15, end fraction radian
iren [92.7K]

Answer:

348 degrees

Step-by-step explanation:

29 pi /15  to degrees

To change from radians to degrees, multiply by 180/pi

29 pi /15 * 180/pi

29 * 180/15

348

8 0
2 years ago
A parallelogram has a base of 9 units and a corresponding height of 2/3 units. What is the area
True [87]
Area or parallelogram = base * height

Area = 9 units * 2/3 units

Area = 9/1 * 2/3 square units

Area = 18/3 square units

Area = 6 square units

Answer: area = 6 square units
4 0
2 years ago
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