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Eddi Din [679]
2 years ago
6

Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55. She can buy 2 containers of yogurt and 2 boxes of cracke

rs for $5.90. How much does one box of crackers cost?

Mathematics
2 answers:
Anna11 [10]2 years ago
6 0

Answer:

The cost of a box of crackers is $2.25.

Step-by-step explanation:

Let the cost of a containers of yogurt is $x and cost of a box of crackers is $y.

It is given that Mandy can buy 4 containers of yogurt and 3 boxes of crackers for $9.55.

4x+3y=9.55              .... (1)

She can buy 2 containers of yogurt and 2 boxes of crackers for $5.90.

2x+2y=5.90              .... (2)

On solving (1) and (2), using graphing calculator, we get

x=0.7

y=2.25

Therefore the cost of a box of crackers is $2.25.

Nitella [24]2 years ago
6 0

Answer:$2.25 i think

Step-by-step explanation:

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Answer:

30 hours

Step-by-step explanation:

so i did 396.10/ 17, and i got 23.3 then u divide his hourly pay by 699.00 and u got 30

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2 years ago
Connor has seven more nickels than dimes and twice as many quarters as dimes. If he has $6.20, how many nickels does he have?
Novosadov [1.4K]
Connor has 16 nickels. If you have 9 dimes (90 cents) and you doubled it that would give you 18 quarters ($4.50). you have 7 more nickels than dimes, so you do 7+9 which equals 16 nickels (80 cents). 90+450+80=620.
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2 years ago
Use the fact that the variance of a Poisson distribution is σ2=μ. The mean number of bankruptcies filed per hour by businesses i
lianna [129]

Answer:

Variance = 5

Standard deviation = 2.236

0.2650257

Step-by-step explanation:

For a Poisson distribution is σ² = μ.

Given that:

Mean , μ of bankruptcies files per hour = 5

μ = 5

For a Poisson distribution :

P(x = x) = (μ^x * e^-μ) / x!

The Variance and standard deviation :

Variance : σ² = μ = 5

Standard deviation = sqrt(variance) = sqrt(5) = 2.236

B.) Find the probability that at most three businesses will file bankruptcy in any given hour.

P( x ≤ 3) = P(0) + P(1) + P(2) + P(3)

P(x = 0) = (5^0 * e^-5) / 0! = 0.0067379

P(x = 1) = (5^1 * e^-5) / 1! = 0.0336897

P(x = 2) = (5^2 * e^-5) / 2! = 0.0842243

P(x = 3) = (5^3 * e^-5) / 3! = 0.1403738

0.0067379 + 0.0336897 + 0.0842243 + 0.1403738

= 0.2650257

6 0
2 years ago
For tall heterozygotes with antennae, the offspring are: tall-antennae 46 dwarf-antennae 7 dwarf-no antennae 42 tall-no antennae
Dmitriy789 [7]

Answer: 46%

Step-by-step explanation:

Recombination frequency =Number of recombinant offspring ÷ total number of offspring × 100%

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Total number of offspring = 46+7+5+42= 100

Recombination frequency= 46/100 × 100%

=46%

Thanks

8 0
2 years ago
The number of frogs living in a pond at time t is modeled by the function y= F(t) that satisfies the logistic differential equat
Keith_Richards [23]

Answer:

from the first model y=F(t)........(1) we have the equation = 25004(1010-y) ..(2).

now you recall that t=0, from equation 1 we now y=F(0)=0.

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Step-by-step explanation:

1. you define variables.

2. you define equations

3. substitute and solve

3 0
2 years ago
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