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ira [324]
2 years ago
12

On a coordinate plane, a line has points (negative 2, negative 4) and (4, 2). Point P is at (0, 4). Which points lie on the line

that passes through point P and is parallel to the given line? Select three options. (–4, 2) (–1, 3) (–2, 2) (4, 2) (–5, –1)
Mathematics
2 answers:
NikAS [45]2 years ago
8 0

Answer:

the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

Step-by-step explanation:

Given that a line passes through two points

A(-2, -4) and B(4, 2)

Another point P(0, 4)

To find:

Which points lie on the line that passes through P and is parallel to line AB ?

Solution:

First of all, let us the find the equation of the line which is parallel to AB and passes through point P.

Parallel lines have the same slope.

Slope of a line is given as:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{2-(-4)}{4-(-2)} = 1

Now, using slope intercept form (y = mx+c) of a line, we can write the equation of line parallel to AB:

y =(1)x+c \Rightarrow y = x+c

Now, putting the point P(0,4) to find c:

4 = 0 +c \Rightarrow c = 4

So, the equation is \bold{y=x+4}

So, the coordinates given in the options which have value of y coordinate equal to 4 greater than x coordinate will be true.

So, the correct options are:

(–1, 3),  (–2, 2) and (–5, –1)

GarryVolchara [31]2 years ago
3 0

Answer:

b,c,e

Step-by-step explanation:

lol

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Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
Effectus [21]
Work the information to set inequalities that represent each condition or restriction.

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3) Model each restriction:

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</span><span>3c + b
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</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
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</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

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4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

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v) You can see such graph in the attached figure.

6 0
2 years ago
Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (
kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2}) is given as continuous function, so there exist lim_{(x,y)\rightarrow(0,0)}f(x,y) and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})

we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19

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8 0
2 years ago
Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number
Masja [62]

Answer:

<h2>√512 by √512 </h2>

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

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If the area of the rectangle is 512m², then 512 = xy

x = 512/y

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P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

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512y⁻² = 1

y⁻² = 1/512

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y²  = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

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Answer:

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Step-by-step explanation:

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4 0
2 years ago
The mechanics at Giuseppe’s Auto House specialize in changing fuel injection units and transmissions. Last week, they changed 5
Lemur [1.5K]

Answer:

The solution is  (2,6)

Step-by-step explanation:

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see the attached figure

4 0
2 years ago
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