Question

If EB =4y-12 and ED= y+17, find the value of y. Then find ED,DB,EB.

Answer 1

Given values of EB and ED are

$EB = 4y-12, ED= y+17$

And from the diagram, we can say that D is the midpoint of EB.

THerefore

$2ED = EB$

Substituting the values of EB and ED, we will get

$2(y+17) = 4y-12 \\ 2y + 34 = 4y -12 \\ 34+12 = 4y-2y \\ 2y=46 \\ y=23$

Therefore,

$ED = y+17 = 23+17 = 40 \\ DB= ED =40 \\ EB= 2 ED = 2*40 =80$