Answer:
El problema es "¿Cuál es la capacidad de solubilidad de los cristales de yodo en diferentes tipos de líquidos?"
Explanation:
Solubilidad es el término que se refiere a la capacidad de las sustancias (solutos) para disolverse en presencia de líquidos (solventes). Así, podemos decir que si Luís quiere saber si los cristales de yodo se pueden disolver en diferentes líquidos, está intentando solucionar el problema de la capacidad de solubilidad de estos cristales.
En este sentido, podemos decir que el yodo no es una sustancia que se disuelva fácilmente en agua, pero sí se puede disolver fácilmente en cloroformo.
Answer:
0.2404
Explanation:
The genes R/r and E/e are linked and there is 4% recombination between them.
<u>The possible genotypes and phenotypes are:</u>
- RR or Rr: Rh+ blood type
- rr: Rh- blood type
- EE or Ee: elliptocytosis
- ee: normal red blood cells
Tom and Terri each have elliptocytosis (they are E_), and each is Rh+ (they are R_).
Tom's mother has elliptocytosis (E_) and is Rh- (rr), so she has the genotype Er/_r. His father is healthy (ee) and has Rh+ (R_), so he has the genotype eR/e_. Tom must have inherited his E allele from his mother and his R allele from his father, so he has the genotype eR/Er.
Terri's father is Rh+ (R_) and has elliptocytosis (E_), while Terri's mother is Rh- (rr) and is healthy (ee) with the genotype er/er. Terry could only receive the chromosome <em>er </em>from her mother, and because she is heterozygous for both genes the dominant alleles were both received from her father. Terri's genotype is ER/er.
The frequency of recombination is 4%, so 4% of the produced gametes will be recombinant. There are two possible recombinant gametes, so each will appear 2% of the times (a frequency of 0.02).
<u />
<u>Tom will produce the following gametes:</u>
- eR, parental (0.48)
- Er, parental (0.48)
- er, recombinant (0.02)
- ER (recombinant (0.02)
<u>Terri will produce the following gametes:</u>
- ER, parental (0.48)
- er, parental (0.48)
- Er, recombinant (0.02)
- eR, recombinant (0.02)
A child Rh- with elliptocytosis has the genotype rrE_. This can happen from the independent combination of the following gametes from Tom and Terri respectively:
- Er (0.48) × er (0.48) = 0.2304 Er/er
- Er (0.48) × Er (0.02) = 0.0096 Er/Er
- er (0.02) × Er (0.02) = 0.0004 er/Er
And the total probability of having a rrE_ child will be 0.2304 + 0.0096 + 0.0004 = 0.2404
Answer:
The DNA double helix unzips.
A strand of RNA is made from a strand of DNA.
The strand of RNA leaves the nucleus.
The strand of RNA moves to the ribosome.
A protein is produced.
Explanation:
During protein production, the messages in DNA are first encoded into mRNA in a process known as transcription. Transcription happens in the nucleus and involves an initial step of unwinding or unzipping of the double helix DNA.
Thereafter, the mRNA produced during transcription is transported from the nucleus to the cytoplasm where it gets attached to the ribosome.
In conjunction with the rRNA and the tRNA, the codons in the mRNA becomes translated into their respective amino acids. The amino acids are then linked by a polypeptide bond leading to the production of protein.
Hence, the correct sequence of event is:
<em>The DNA double helix unzips.</em>
<em>A strand of RNA is made from a strand of DNA.</em>
<em>The strand of RNA leaves the nucleus.</em>
<em>The strand of RNA moves to the ribosome.</em>
<em>A protein is produced.</em>
The correct answer is: D. The red blood cells were placed in a hypotonic solution. Water moved from the outside of the cells to the inside of the cells until the cells burst.
Hypotonic solution can be described as solution that has less solute and more water (H2O) than another solution. In order to maintain homeostasis, the water will move (via osmosis) into the cell, through the semipermeable membrane of the red blood cell.
Student 1’s methods would be more accurate, because the student would control more factors. Only one variable at a time (either temperature or acidity) would be tested on each group of worms. On the other hand, Student 2 is testing both factors on all the worms, which could make the results unclear.
