Question

an urn contains balls numbered 1 to 15 a ball is chosen returned to the urn and the second ball is chosen what is the probability that the first and the second of all will be a six

Answer 1

Answer:

$\frac{2}{15}$

Step-by-step explanation:

An urn contains balls numbered from 1 to 15

Total number of outcomes= 15

Let E1 be event of getting a ball numbered 6

Favorable case to E1= 1

Probability=$\frac{favourable case}{total number of outcomes}$

P(E1)= $\frac{1}{15}$

A ball is chosen and returned to urn

Again, total number of outcomes=15

Let E2 be event of getting a ball numbered 6

Favorable case to E2= 1

P(E2)= $\frac{1}{15}$

The Probability that the first and second ball is 6=P(E1)+P(E2)

=$\frac{1}{15}$+$\frac{1}{15}$

=$\frac{2}{15}$

Hence, the correct answer is $\frac{2}{15}$

Answer 2

1/30 chance I think. 1/15 and 1/15