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babunello [35]
2 years ago
15

choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6. y = −6x − 15 y = −6x −

20 y = −6x 15 y = −6x 20
Mathematics
2 answers:
wolverine [178]2 years ago
7 0
We can solve this in a number of ways: using the point-slope formula, using trial and error or by inspection.

Using the point-slope formula:
y - y1 = m (x - x1)
y - (-3) = (-6) (x - (-2))
y + 3 = -6x - 12
y = -6x - 12 - 3
y = -6x - 15

Therefore, the answer is the first option.
docker41 [41]2 years ago
5 0

Answer:

y=-6x-15

Step-by-step explanation:

Using the point-slope formula:

y - y1 = m (x - x1)

y - (-3) = (-6) (x - (-2))

y + 3 = -6x - 12

y = -6x - 12 - 3

y = -6x - 15

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Jeff earned his pilot's license and flew to visit his brother 200 miles away. A headwind of 20 mph slowed down the plane's speed
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<h2>Plane's speed without wind i s 117.68 mph</h2>

Step-by-step explanation:

We have speed of plane without wind is x.

Distance to brothers place = 200 miles.

A headwind of 20 mph slowed down the plane's speed on the first leg of the trip

Speed to brothers place = x - 20

We have

         Distance = Speed x Time

         200=(x-20)\times t_1\\\\t_1=\frac{200}{x-20}

A tailwind of 20 mph sped up the plane on the return trip

Speed of return trip = x + 20

We have

         Distance = Speed x Time

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The entire trip took 3.5 hours.

That is

            t_1+t_2=3.5\\\\\frac{200}{x-20}+\frac{200}{x+20}=3.5\\\\200x+4000+2000x-4000=3.5(x-20)(x+20)\\\\400x=3.5x^2-1400\\\\7x^2-800x-2800=0\\\\\texttt{x = 117.68mph or x =-3.40mph}

Plane's speed without wind i s 117.68 mph

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(3x³ + 2x - 3) - (4x³ - x² + x)

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