Question

An isosceles triangle has a vertex angle of 26°. Two sides of the triangle are each 15 ft long. Find the area of the triangle.

Answer 1

Answer: Area of isosceles triangle would be 49.32 sq. ft.

Step-by-step explanation:

Since we have given that

Measure of vertex angle of an isosceles triangle = 26°

Length of each side of the triangle = 15 feet

So, Area of triangle would be

$\dfrac{1}{2}\sin \theta\times a\times b\\\\=\dfrac{1}{2}\times \sin 26^\circ\times 15\times 15\\\\=49.32\ ft^2$

Hence, area of isosceles triangle would be 49.32 sq. ft.

Answer 2

Area (A) of a triangle = 1/2 · side1 · side 2 · sin of vertex angle

A = 1/2 · 15 · 15 · sin 26°

A = 225/2 · sin 26

A = 112.5 · .438

A = 49.32

Answer: 49.32 ft²