Answer:
gene encoding enzymes for glycolysis.
Explanation:
Plasmid may be defined as an extra chromosomal circular DNA that replicate independently of the main chromosomal material. Plasmid are generally used for the manipulation of genes in molecular technologies.
Plasmid can encode gene for toxins, antibacterial resistance and for the unusual substrate degradation. The plasmid cannot code enzyme for glycolysis because these enzymes are already present in the host organisms. Glycolysis enzymes are independent on the plasmid regulation.
Thus, the correct answer is option (3).
Growth Hormone and insulin are protein hormones that promotes the growth and regulation of substrate metabolism.
Explanation:
The Growth Hormone performs the metabolic actions in various tissues like liver, muscle, and pancreas through insulin growth factor. Insulin slows down the growth hormone signalling through the growth hormone receptor. It is important for maintaining the responsiveness of liver to growth hormone.
The insulin signalling pathway is very important in metabolic diseases like diabetes and aging. These insulin activates a phosphorylation cascade that branches to form a network affecting multiple biological processes.
The altered protein affected the function of the cell membrane. The cell membrane which contain a bilayer control the movement of substance in and out of the cell and organelles. Due to this it is selective permeable to ion and organic molecules.
Answer:
D. 0.60
Explanation:
If the population is in Hardy-Weinberg equilibrium, the genotypic frequencies are:
- freq AA = p²
- freq Aa = 2pq
- freq aa = q²
<em>p</em> is the frequency of the Rh positive allele (A) and <em>q</em> is the frequency of the Rh-negative allele (a).
If 84% of the population is Rh-positive, then 16% is Rh-negative and has the genotype <em>aa</em>. Therefore:
q² = 0.16
q = √0.16
q=0.4
And because p+q=1,
p = 1 - 0.4
p = 0.6
The frequency of the Rh-positive allele is 0.6
