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aalyn [17]
2 years ago
4

Giuliana has 22 quarters and dollar coins worth a total of $10.75.

Mathematics
2 answers:
deff fn [24]2 years ago
7 0

Answer:

c

Step-by-step explanation:

Maslowich2 years ago
6 0

Answer:

C. 0.25(22-d)+d=10.75

Step-by-step explanation:

Let d represent the number of dollar coins.

We have been given that Giuliana has 22 quarters and dollar coins. So number of quarter coins would be 22-d.

We know that value of a quarter is $0.25. So all quarter coins will be worth 0.25(22-d)

We are also told that these coins worth a total of $10.75. This means that d dollar coins and 0.25(22-d) worth 10.75. We can represent this information in an equation as:

0.25(22-d)+d=10.75

Therefore, option C is the correct choice.

Upon solving our equation we will get,

5.5-0.25d+d=10.75

5.5+0.75d=10.75\

5.5-5.5+0.75d=10.75-5.5

0.75d=5.25

\frac{0.75d}{0.75}=\frac{5.25}{0.75}

d=7

Therefore, Guiliana had 7 dollar coins.

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See Below

Step-by-step explanation:

The function is a piecewise function defined as:

N(t)=\left \{ {{25t+150} \ 0 \leq t \leq 6 \atop {\frac{200+80t}{2+0.05t} \ t \geq 8}} \right.

a)

We need to find the limit of the function as t goes to infinity. This means what is the max value of fish in the pond given times goes to infinity (on an on).

We will take the 2nd part of the equation since t falls into that range, t is infinity, which is definitely greater than 8.

\lim_{t \to \infty} \frac{200+80t}{2+0.05t} \\\lim_{n \to \infty} \frac{80t}{0.05t}\\ \lim_{n \to \infty} \frac{80}{0.05} =1600

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b)

A function is continuous at a point if we have the limit and the functional value at that point same.

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We want to find is there a "time" when the number of fishes in the pond is 250, during t from 0 to 6. We plug in 250 into N(t) and try to find t. Make sure to use the 1st part of the piece-wise function. Shown below:

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The time is 4 years when the number of fishes in the pond is 250

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50 years ... 2.5 degrees
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Answer:


Step-by-step explanation:

Given is an algebraic polynomial of degree 5.

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