Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
The student made a mistake in Line 1: AC=2, DF=2 AC ≅ DF .
Answer:
1kg of salami cost $9.1
Step-by-step explanation:
Hailey paid $13 for 1 3/7 kg of sliced salami.
What was the cost per kilogram of salami?
Cost of 1 3/7 kg of sliced salami=$13
1 3/7 kg=10/7kg
Let x=1 kg of sliced salami
10/7 kg of x=$13
$13=10/7x
13=10/7*x
x=13 ÷ 10/7
=13×7/10
=91/10
=9.1
x=$9.1
Therefore, 1kg of salami cost $9.1
Answer:
He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True
He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True
He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False
He used the points that were marked along the circumference of the original circle as the vertices for the square. True
Step-by-step explanation:
Performance matters test perhaps?