Here, regrouping is basically carrying.
64+43 shown vertically would be:
64
+43
-------
107
4+3 is 7, so seven is in the ones place, but that's not the point.
60+40 is 100, so you regroup by carrying the one to the hundreds place.
Hope I helped!
<h3>
Answer: 97/112</h3>
================================================
How to get this answer:
Midpoint formula: (A+B)/2 = C
A and B are the endpoints with C as the midpoint
A = 7/8
B = 6/7
A+B = 7/8 + 6/7
A+B = 49/56 + 48/56
A+B = (49+48)/56
A+B = 97/56
(A+B)/2 = (97/56) divided by 2
(A+B)/2 = (97/56) times (1/2)
(A+B)/2 = (97*1)/(56*2)
(A+B)/2 = 97/112
One person recieves 1. Second person receives 2. Third person receives 3. The amount of cards left over is 94. So the fourth person receives the highest amount possible with everyone in positive numbers of cards.
Answer: The guy wires will make a 54 degree angle with the ground.
Start by drawing a right triangle. The hypotenuse will be 80 and the side opposite our angle will be 65.
Since we are working with the opposite side and hypotenuse, we can write and solve the sin equation below.
Sin(X) = 65/80 (Take the inverse sign of both sides)
x about 54 degrees
Answer:
Dylan will not have enough money. He needs $22.65 but only has $22.50
Step-by-step explanation:
If Dylan's mom replaces each dime with a quarter, then Dylan will have 90 quarters.
1 Quarter = $0.25
90 x .25 = $22.50
The game costs $20.98 plus 8% sales tax
So 20.98 x .08 = <em>$</em><em>1.6784</em>
20.98 + 1.6784 = $22.65
<em>Dylan</em><em> </em><em>will</em><em> </em><em>not</em><em> </em><em>have</em><em> </em><em>enough</em><em> </em><em>money</em><em> </em><em>because</em><em> </em><em>he</em><em> </em><em>only</em><em> </em><em>has</em><em> </em><em>$</em><em>2</em><em>2</em><em>.</em><em>5</em><em>0</em><em> </em><em>when</em><em> </em><em>he</em><em> </em><em>needs</em><em> </em><em>$</em><em>2</em><em>2</em><em>.</em><em>6</em><em>5</em>