Answer:
6.1389 x 10^8
Step-by-step explanation:
100 tickets were sold.
The total amount of the tickets sold is = 5 * 100 = $500.
First prize given = $100
Second prize worth = $20 * 5 = $100
Total worth of prize + $100 + $100 = $200.
Net amount of tickets sold = $500 - $200 = $300
Expected price of each ticket sold = $300/100 = 3.
Therefore, the real price of each ticket sold is $3.
X + (7 - 3i) + (5 + 9i) + 13i = 10 - 5i
Subtract 13i from both sides
x + (7 -3i) + (5 + 9i) = 10 - 18i
Subtract (5 + 9i). MAKE SURE YOU SUBTRACT 9i TOO. In other words, distribute the negative and subtract 5 and 9i at the same time.
x + (7 - 3i) = 5 - 27i
Do the same with (7 - 3i). You'll be adding 3i since -(-3i) = 3i.
x = -2 - 24i
The dimensions of the base of Box 1 are x by 3x.
The base area of Box 1 is:
3x^2
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.