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kumpel [21]
2 years ago
4

GI bisects <DGH so that m <DGI is x-3 and m<IGH is 2x-13.FIND the value of x.

Mathematics
2 answers:
alexandr1967 [171]2 years ago
6 0

If GI bisects ∠DGH, then

∠DGI≅∠IGH and  m∠DGI=m∠IGH.

Thus,

x-3=2x-13.

Solve this equation:

x-2x=-13+3,

-x=-10,

x=10.

Answer: x=10.

DerKrebs [107]2 years ago
5 0

Answer:

the answer is x=10

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A worker has a base pay of $20 per hour, gets $3 more per hour after 8 hours, and gets $4 more
GalinKa [24]

Answer:

177 $

Step-by-step explanation:

20 x8 = 160

3x3= 9

4x2=8

8+9+160= 177

6 0
2 years ago
If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal
Vera_Pavlovna [14]

Answer:

y''=-1.26

Step-by-step explanation:

We are given that 2x^2+y^2=17

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

4x+2yy'=0

2x+yy'=0

yy'=-2x

y'=-\frac{2x}{y}

Again differentiate w.r.t.x

Then , we get

2+(y')^2+yy''=0 (u\cdot v)'=u'v+v'u)

2+(y')^2+yy''=0

Using value of y'

yy''=-2-(-\frac{2x}{y})^2

y''=-\frac{2+(-\frac{2x}{y})^2}{y}

Substitute x=2 and y=3

Then, we get y''=-\frac{2+(\frac{4}{3})^2}{3}

y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}

Hence,y''=-1.26

6 0
2 years ago
In the diagram, P1P2 and Q1Q2are the perpendicular bisectors of AB¯¯¯¯¯ and BC¯¯¯¯¯, respectively. A1A2 and B1B2 are the angle b
4vir4ik [10]
We have to choose the correct answer for the center of the circumscribed circle of a triangle. The center of the circumscribed circle of a triangle is where the perpendicular bisectors of a triangle intersects. In this case P1P2 and Q1Q2 are perpendicular bisectors of sides AB and BC, respectively and they intersect at point P. S is the point where the angle bisectors intersect ( it is the center of the inscribed circle ). Answer: <span>P.</span>
7 0
2 years ago
vegetable ghee is stored in the cylindrical vessel of internal radius 1.4m height 1.5m. if it is transferred into the rectangula
irina1246 [14]

Answer:

<em>5,598 cans are required to empty the vessel</em>

Step-by-step explanation:

The volume of a cylinder of radius r and height h is:

V = \pi r^2h

The volume of a box of dimensions X, Y, and Z is:

V=X.Y.Z

A cylinder of r=1.4 m and height h=1.5 is used to store vegetable ghee. It contains a volume of:

V_1 = \pi 1.4^2*1.5

V_1=9.236\ m^3

Converting to cubic cm:

V_1=9.236*1,000,000\ cm^3

V_1=9,236,282\ cm^3

The volume of each rectangular tin can is:

V_2=33*10*5=1,650\ cm^3

V_2=1,650\ cm^3

The number of cans required to empty the vessel is:

V_1/V_2=9,236,282/1,650 = 5,598

5,598 cans are required to empty the vessel

5 0
2 years ago
The function f(x) = 1/2 x + 3/2 is used to complete this table.
Mrac [35]

Answer:

a) f(-1/2)  = -2 is NOT TRUE.

b)  f(0)  =3/2 is  TRUE.

c)   f(1)  = -1 is NOT TRUE.

d)   f(2)  = 1 is NOT TRUE.

e)   f(4)  = 7/2  is  TRUE.

Step-by-step explanation:

Here, the given function is  f(x) = (\frac{1}{2}) x+\frac{3}{2}

Now, checking for each values for the given function:

a) Putting x  = (-1/2):

 f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2}   = \frac{-1}{4}  + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4}  = (\frac{5}{4} )

and (5/4) ≠  -2

Hence, f(-1/2)  = -2 is NOT TRUE.

b)Putting x  = 0 :

f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )

Hence, f(0)  =3/2 is  TRUE.

c) Putting x  = 1:

f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2}   = \frac{1}{2}  + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2}  = (\frac{4}{2} )   = 2\implies 2   \neq -1

Hence, f(1)  = -1 is NOT TRUE.

d)Putting x  = 2:  

f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2}   = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2}  = (\frac{5}{2} )

and (5/2) ≠  1

Hence, f(2)  = 1 is NOT TRUE.

e)Putting x  = 4:

 f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2}   = 2  + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2}  = (\frac{7}{2} )

Hence, f(4)  = 7/2  is  TRUE.

4 0
2 years ago
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