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Ber [7]
2 years ago
6

The main reason that proteins outperform other macromolecules in terms of catalytic ability is because ____. See section 3.4 (pa

ge
Biology
2 answers:
ser-zykov [4K]2 years ago
7 0

Among the four main biological macro-molecules, the proteins are capable of outperforming the others as far as their catalytic ability is concerned. This ability of the proteins to outshine in terms of catalytic activity is because of the presence of they contain a variety of the alkyl (R) groups. These alkyl groups attached to the chains of proteins enhances the catalytic activity.

Hence, the given blank can be filled with 'variety of alkyl groups'.

Svetradugi [14.3K]2 years ago
7 0

Answer;

-Proteins can contain a variety of R groups

Explanation;

-All amino acids have the alpha carbon bonded to a hydrogen atom, carboxyl group, and amino group. The R group varies among amino acids and determines the differences between these protein monomers.

Hydrogen bonds in secondary structure involve the polar amino and carboxyl groups of amino acids, but do not involve R-groups.As the peptide chain continues to grow, interactions between amino acid side chains (R-groups) form the tertiary structure of a polypeptide.

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A contraction of the smooth muscle in the walls of the bronchi and bronchioles that tighten and squeeze the airway shut is known
Romashka [77]

Answer:

Bronchospasm

Explanation:

Bronchospasm is known to be a condition that results from the contraction of the muscles that is found in the wall of the bronchioles which result into obstruction and narrowing of the respiratory airway. Thus, substance released from basophils or mast cell under the control of anaphylatoxin usually causes Bronchospasm. Furthermore, Bronchospasm is commonly caused by asthma and can also be caused by allergic reactions, respiratory infection, and chronic lung diseases.

3 0
2 years ago
Briefly explain why it is necessary to critique a scientific argument before it is accepted.
Alenkasestr [34]
To be accepted, a scientific argument must first proved it's solidity and validity and critiques from other expert is usually the best way to explain both the solidity and the validity of a scientific argument

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3 0
2 years ago
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After watching the squirrels at the local park for several days, Sergei asks his science teacher the following question: "Do mor
KiRa [710]
This is a scientific question because you could conduct an experiment to test the theory.
 
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2 years ago
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Pseudomonas sp. has a mass doubling time of 2.4 h when grown on acetate. The saturation constant using this substrate is 1.3 g/l
erastova [34]

Answer:

a)  Cell concentration when the dilution rate is one-half of the maximum is  0.598g cell/L

b) the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c) the maximum dilution rate is : 0.41 h⁻¹

d)  the cell productivity at 0.8  D_{max}   is 2.40g cell/L

Explanation:

Given data :

Mass doubling time of Pseudomonas sp. = 2.4 hr

Saturation constant = 1.3 g/L

Cell yield  on acetate = 0.46g cell/g acetate

We are to find;

a. Cell concentration when the dilution rate is one-half of the maximum.

Here, cell yield =amount of cell produced / amount of substrate consumed.

[S] at 0.5D max is determined using the Monod's equation.

Using the formula :

D = \frac {D_{max}[S] }{ks+[S]}

, where D is the dilution rate,

[S] is substrate concentration; &

Ks is the saturation constant.

By replacing the values, we get :

0.5 = \frac{S}{1.3+[S]}

\\\0.65=0.5[S]

[S]=1.3g/L

The cell concentration at 0.5Dmax= cell yield x substrate consumed at 0.5Dmax.

=0.46×1.3

= 0.598g cell/L

b)

Substrate concentration when the dilution rate is 0.8 D_{max}    is calculated as:

D = \frac {D_{max}[S] }{ks+[S]}

0.8=[S]/1.3+[S]

1.04+0.8[S]=[S]

[S]= 5.2g/L

Therefore ,  the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c)

Maximum dilution rate is calculated using the expression D_{max} = \frac{1}{time}

=1/2.4

=0.41 h⁻¹

So, the maximum dilution rate is : 0.41 h⁻¹

d)

The cell productivity at 0.8 D_{max} can be calculated by multiplying the amount  of the cell yield with the amount of the substrate consumed at 0.8D_{max}  

Cell yield = \frac {cell \ productivity \ at \  0.8Dmax}{amount \ of \ substrate\ consumed \at\ 0.8 \D_{max}}

Cell productivity at 0.8 D_{max}    = 0.46 × 5.2

=2.40g cell/L

Therefore, the cell productivity at 0.8  D_{max}   is 2.40g cell/L

5 0
2 years ago
The gray matter in the spinal cord is located in the ____________ , and its shape resembles a letter H, or a butterfly. The cell
mariarad [96]

Answer:

The gray matter in the spinal cord is located in the <u><em>grey column</em></u> , and its shape resembles a letter H, or a butterfly. The cell bodies of somatic motor neurons are primarily housed in the <u><em>ventral or anterior</em></u> horns, which innervate skeletal muscle.

Explanation:

The grey matter is a component of the central nervous system that contains neuronal and glial cells and it can be found in the brain, brainstem and <em>spinal cord, in this last one, is found in the grey column, a mass of grey matter shaped in H form.</em>

In this column the grey matter is divided into four columns (as you can see in the image I added):

  • The dorsal or posterior horn: contains somatosensorial neurons
  • <em> The ventral or anterior horn: contains somatic efferent motor neurons (they exit the spinal cord to innervate skeletal muscle) </em>
  • The intermediate column: contains neurons to innervate visceral organs
  • The lateral horn: same as the intermediate column

I hope you find this information useful and interesting! Good luck!

6 0
1 year ago
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