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Ber [7]
2 years ago
6

The main reason that proteins outperform other macromolecules in terms of catalytic ability is because ____. See section 3.4 (pa

ge
Biology
2 answers:
ser-zykov [4K]2 years ago
7 0

Among the four main biological macro-molecules, the proteins are capable of outperforming the others as far as their catalytic ability is concerned. This ability of the proteins to outshine in terms of catalytic activity is because of the presence of they contain a variety of the alkyl (R) groups. These alkyl groups attached to the chains of proteins enhances the catalytic activity.

Hence, the given blank can be filled with 'variety of alkyl groups'.

Svetradugi [14.3K]2 years ago
7 0

Answer;

-Proteins can contain a variety of R groups

Explanation;

-All amino acids have the alpha carbon bonded to a hydrogen atom, carboxyl group, and amino group. The R group varies among amino acids and determines the differences between these protein monomers.

Hydrogen bonds in secondary structure involve the polar amino and carboxyl groups of amino acids, but do not involve R-groups.As the peptide chain continues to grow, interactions between amino acid side chains (R-groups) form the tertiary structure of a polypeptide.

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imagine you have data on the jaw structure of hundreds of species, and information about what each species ate. How could you us
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shoot a irish spring green like flight

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Identify and describe a cellular division process that could be used by trichoplax when it reproduces asexually HELP I ONLY HAVE
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<h3><u>Answer and explanation;</u></h3>

<u>Binary Fission. </u>

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8 0
1 year ago
A unicellular organism that produces glucose through photosynthesis would most likely contain which structure
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4 0
1 year ago
In pea plants, the allele for tall stalks (T) is dominant over the allele for short stalks (t). Suppose a cross between a tall p
vazorg [7]

Answer:

Tt - 1/2

tt - 1/2

Explanation:

<em>A cross between a tall pea plant and a short pea plant that produces 43 tall and 47 short offpsring (almost 1:1) is most likely a cross involving a heterozygous tall individual and a homozygous short individual.</em>

Tt   x   tt

Offspring = Tt   Tt   tt   tt (50% tall and 50% short)

If one of the tall offspring (Tt) is crossed with one of the short offspring (tt):

Tt   x   tt

Offspring = Tt   Tt   tt   tt

Genotype ratio = 2Tt:2tt

Hence,

Tt = 1/2

tt = 1/2

6 0
2 years ago
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