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zhuklara [117]
2 years ago
12

Dry climates often favor the development of great dry grasslands called A) deserts B) forests C) savannas D) tundras

Biology
2 answers:
zaharov [31]2 years ago
6 0
C.) Savanna's hope this helps
Flauer [41]2 years ago
5 0
The answer would be, "C", "Savannas". 
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The Big Five trait dimension or the five factor model is based on descriptors of personality. The big five traits are:

Openness
Beuroticism
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From these, the trait expressed is Extraversion. This trait is characterized by outgoing and energetic behavior. Energy creation is gained through external means. 
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2 years ago
Scientists are researching a large family, many of whose members have Jackson-Weiss Syndrome, a disease that causes bone problem
Goryan [66]

The right answer is C.

A genetic disease is called autosomal dominant transmission when :

* The morbid allele ("sick" version, mutated of the gene in question) is on a non-sexual chromosome (neither X nor Y).

* The presence of a single morbid allele is sufficient for the disease to express itself.

The morbid allele is transmitted by either the father or the mother (or both, if they have the same inherited autosomal dominant genetic disease). Anyone with one of their affected parents is affected.

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1 year ago
What do sphincter muscles do? a. Trigger hormone release. b. Control peristalsis. c. Secrete digestive juices into the GI tract.
Maksim231197 [3]

Answer:

Answer is E.

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* Cardiac sphincter...found at the upper area or portion of the stomach.

* Pupilary sphincter..found in the iris of the eye.

* Glisson's sphincter...controlling the secretion of the gall bladder,pancrease and the liver.

6 0
2 years ago
Why does a needle left out in the sun get so much hotter than a bucket of water left out in the sun
Hitman42 [59]
The correct answer is 

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5 0
2 years ago
Read 2 more answers
Pseudomonas sp. has a mass doubling time of 2.4 h when grown on acetate. The saturation constant using this substrate is 1.3 g/l
erastova [34]

Answer:

a)  Cell concentration when the dilution rate is one-half of the maximum is  0.598g cell/L

b) the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c) the maximum dilution rate is : 0.41 h⁻¹

d)  the cell productivity at 0.8  D_{max}   is 2.40g cell/L

Explanation:

Given data :

Mass doubling time of Pseudomonas sp. = 2.4 hr

Saturation constant = 1.3 g/L

Cell yield  on acetate = 0.46g cell/g acetate

We are to find;

a. Cell concentration when the dilution rate is one-half of the maximum.

Here, cell yield =amount of cell produced / amount of substrate consumed.

[S] at 0.5D max is determined using the Monod's equation.

Using the formula :

D = \frac {D_{max}[S] }{ks+[S]}

, where D is the dilution rate,

[S] is substrate concentration; &

Ks is the saturation constant.

By replacing the values, we get :

0.5 = \frac{S}{1.3+[S]}

\\\0.65=0.5[S]

[S]=1.3g/L

The cell concentration at 0.5Dmax= cell yield x substrate consumed at 0.5Dmax.

=0.46×1.3

= 0.598g cell/L

b)

Substrate concentration when the dilution rate is 0.8 D_{max}    is calculated as:

D = \frac {D_{max}[S] }{ks+[S]}

0.8=[S]/1.3+[S]

1.04+0.8[S]=[S]

[S]= 5.2g/L

Therefore ,  the substrate concentration when the dilution rate is 0.8 D_{max}   is 5.2g/l

c)

Maximum dilution rate is calculated using the expression D_{max} = \frac{1}{time}

=1/2.4

=0.41 h⁻¹

So, the maximum dilution rate is : 0.41 h⁻¹

d)

The cell productivity at 0.8 D_{max} can be calculated by multiplying the amount  of the cell yield with the amount of the substrate consumed at 0.8D_{max}  

Cell yield = \frac {cell \ productivity \ at \  0.8Dmax}{amount \ of \ substrate\ consumed \at\ 0.8 \D_{max}}

Cell productivity at 0.8 D_{max}    = 0.46 × 5.2

=2.40g cell/L

Therefore, the cell productivity at 0.8  D_{max}   is 2.40g cell/L

5 0
2 years ago
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