Answer:
The answer is XX.
Explanation:
Let us say that X is the dominant gene and x is the recessive gene for the height of the pea plants. Pea plants need to be homozygous or heterozygous to have the short phenotype which means it needs to have the genotype xx or Xx.
The F2 offspring has a ratio of 74,5% tall plants and 25,5% short plants. For these results, the stem height pea plant needs to be homozygous which is an XX genotype for the tall pea plant.
I hope this answer helps.
Answer:
The answer is B.
Explanation:
The variable is dependent meaning it stands on its own. the sentence "I skipped dinner" is a stand alone sentence meaning its the answer
A muskrat population is growing exponentially. What might cause this population to enter logistic growth?
Answer: One cause that might cause the population of this semi aquatic rodents to enter a logistic growth would be the elimination of predators from their environment and the increase of food. The reason being that they are rodents with an adaptable lifestyle and an omnivorous diet. With no predators they would quickly adapt to their environment and increase their birth rate.
I hope it helps, Regards.
Answer: a. Genetic recombination (crossing over)
b. Can also be explained in terms of crossing over
c. Non disjunction of homologous chromosomes in meiosis 1
Explanation:
The process that allows for the transfer of both the paternal and maternal materials to is the crossing over process that takes at meiosis 1 changing them to secondary spermatocytes. While they are still primary spermatocytes, they are still diploid cells having both the maternal and paternal chromosomes. But since the spermatozoon is an haploid cell, it is able to retail some of both parents chromosome by the crossing over event which takes place between homologous paternal and maternal chromosomes allowing them to exchange materials. Thus the chromosomal contents of the primary spermatocyte differs from that of the spermatozoon.
C. This can occur as a result of the one of the homologous chromosome pair refusing to separate at meiosis 1 with one gamete containing 4 chromosomes/8 sister chromatids and the second having 2 chromosomes/4 sister chromatids.
Answer:
QP = 41
Explanation:
Its geometry its easy...
Since its getting cut through the middle that means they equal each other
3x + 5 = 5x - 19 (Use a calculator)
x = 12
Since your solving to find QP you plug it into QP
3(12) + 5 = 41
:)
