Answer:
Uneven use of resources
Explanation:
Potential problem associated with supporting multi - user operation without hardware support is:
Uneven use of resources: In a situation where we assign a set of resources to user 1 and if a new user comes, then it would be difficult to allocate new resources to him. The processor would get confused between the two users. And the tasks would not be completed. This can affect task processing.
Answer:
It will be a java code.
Explanation:
import java.util.Scanner;
public class StringInputStream {
public static void main (String [] args) {
Scanner inSS = null;
String userInput = "Jan 12 1992";
inSS = new Scanner(userInput);`
String userMonth = "";
int userDate = 0;
int userYear = 0;
/* Your solution goes here */
System.out.println("Month: " + userMonth);
System.out.println("Date: " + userDate);
System.out.println("Year: " + userYear);
return;
}
}
Answer:
The correct answer is:
a. M54.6, C79.51, C80.1
Explanation:
- M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.
Malignant neoplasm of anus, unspecified
Neoplasm related pain (acute) (chronic)
Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.
Malignant (primary) neoplasm, unspecified
- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.
Answer: $1,500
Explanation:
The future value of value using simple interest is:
Future value = Value * ( 1 + rate * time)
2,400 = Value * (1 + 15% * 4)
2,400 = Value * 1.6
Value = 2,400 / 1.6
Value = $1,500
<span>An attribute in a relation of a database that serves as the primary key of another relation in the same database is called a
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