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Arturiano [62]
2 years ago
5

Write an improper fraction whose value is between 5 and 10, and whose denominator is 4

Mathematics
1 answer:
sveta [45]2 years ago
5 0

8/4 should work, because the numerator's higher than the denominator.

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A Cepheid star is a type of variable star, which means its brightness is not constant. The relationship between the brightness o
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Answer:

The absolute brightness of the Cepheid star after a period of 45 days is -5.95

Step-by-step explanation:

Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by

M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.

From our question, it is given that P = 45 days.

So, M = –2.78(log P) – 1.35

M = –2.78(log 45) – 1.35

M = –2.78(1.6532) – 1.35

M = -4.60 - 1.35

M = -5.95

So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95

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2 years ago
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After dinner 3/4 of a pie remains. if tasha eats 1/6 of the remaining pie
astraxan [27]

Answer: 1/8

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4 0
2 years ago
Find the difference 18,354 4,672
attashe74 [19]

Answer:

18,354 - 4,672= 13,682

Step-by-step explanation:

I'm not sure what you meant but above is the answer of what I think you were asking.

6 0
2 years ago
What is 6.37 × 104 written in standard form?   A. 63,700   B. 637,000   C. 6370   D. 637
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= 6.37 * 10^4 = 637 * 10^2 = 63700

In short, Your Answer would be Option A

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8 0
2 years ago
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The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca
dem82 [27]

Answer:

\frac{4}{663}

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

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We have to find probability for

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P(A) = no of 4s in the deck/total cards = \frac{4}{52} =\frac{1}{13}

After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it

P(B) = no of Aces in 51 cards/51 = \frac{4}{51}

Hence

P(A\bigcap B) = \frac{1}{13} *\frac{4}{51} \\=\frac{4}{663}

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)

8 0
2 years ago
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