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mr_godi [17]
2 years ago
5

Selina claims single having one exemption. Her state tax deduction is 21% of her federal tax contribution. Calculate the amount

of state tax Selina owes if her gross pay for two weeks is $840.
The following federal tax table is for biweekly earnings of a single person.
a.
$16.17
b.
$16.80
c.
$32.34
d.
$33.60
Mathematics
2 answers:
alekssr [168]2 years ago
8 0
Need the tax table to answer the questuon
borishaifa [10]2 years ago
7 0

Answer:

b. $16.80

Step-by-step explanation:

On the lefthand-most column, you find the row for $840. Then, at the top row, it indicated the exemption. Since Selina has a single exemption, find the column with 1 in it. The intersection of the designated row and columnis Selina's withheld amount. That would be 80. We find the 21% of this.

80*0.21 = $16.8

Thus, Selina's amount of state tax will be $16.8.

Read more on Brainly.com - brainly.com/question/2268078#readmore

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Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

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Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

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Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

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