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Andru [333]
2 years ago
15

Determine by inspection whether the vectors in exercises 15–20 are linearly independent. justify each answer.

Mathematics
1 answer:
Ymorist [56]2 years ago
7 0
You need to include an image
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Frank had hip replacement surgery and was given a prescription with instructions to take a 200 milligram (mg) tablet three times
IgorC [24]

Answer:

12,600mg per 21 days

Step-by-step explanation:

200mg three times a day → (200mg)(3) = 600mg per a day

21 days → (21)(600mg) = 12,600mg per 21 days

5 0
2 years ago
The town council wants to know if the residents support beautification of the downtown area. What is the best design for this st
Natasha_Volkova [10]
Experimental census sample survey

7 0
2 years ago
fourteen boys and 21 girls will be equally divided into groups. Find the greatest number of groups that can be created if no one
shtirl [24]
Well if you add 14 and 21 you get 35. with 35 you can have 7 groups of 5 but if they have to be equal with the number of boys and girls in each group it would still be 7. two boys in each group with three girls in each group.
6 0
2 years ago
A company administers an "aptitude test for managers" to aid in selecting new management trainees. Prior experience suggests tha
RoseWind [281]

Answer:

0.94

Step-by-step explanation:

The question after this basically is:

<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>

<em />

So,

P(successful if hired) = 60% = 0.6 [let it be P(x)]

P(success at passing the test) = 85% = 0.85   [let it be P(y)]

P(successful and pass the test) =  P(x) + P(y) -[P(x)*P(y)]

So,

P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)

5 0
2 years ago
Identify the 12th term of the geometric sequence in which a2 = −6 and a6 = −96
timurjin [86]
a_2=-6;\ a_6=-96\\\\a_6:a_2=r^4\\\\r^4=-96:(-6)\\\\r^4=16\\\\r=\sqrt[4]{16}\\\\r=2\\\\a_{12}=a_6r^6\\\\a_{12}=-96\cdot2^6=-96\cdot64=-6,144
6 0
2 years ago
Read 2 more answers
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