Answer:
The claim by the researcher is supported because of the known functions of insulin and growth factors. Both hormones have a tendency to respond to the presence of glucose. The growth hormone initiates STAT5 signaling for producing the Igf-1 factor that is important for utilizing glucose. The insulin hormone is well known for utilizing glucose.
The correct answers are evolution, genetic mutation and selection.
The early ancestors of horses showed the pressence of digits and now the modern horses have hooves in their limbs. There could be many reasons for the pressence of hooves horses.
These could be due to the genetic mutations, which could have changed the shape of the digits in the limb. Sudden change in DNA can cause mutation and this mutation can change the phenotype of the horse.
There are chances that evolution took place over a period of time that changed the character in the horse.
Natural selection can also be one of the reason for the change in the phenotype of the digits on the limb of the horses.
<span>The barn owl's right ear opens slightly upward while its left ear opens slightly downward. this difference enables the owl to detect the location of a sound. It would actually depend on the location of where it would be at, and based on this, depending where it would then be located, this would then be able to differentiate where it would be located.</span>
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Answer:
Convergent.
Explanation:
The collision between two lithosphere plates on the surface of earth results in the formation of convergent plate boundaries. The process of subduction occurs when one plate converges over the other plate.
The diagram given in the question shows the convergent plate boundary. The collision of two lithospheric plates have been represented in the picture.
Thus, the correct answer is option (A).
